Answer:
3.
Step-by-step explanation:
sin 32 / (1 + tan 45) * 6 / cos 58
= sin 32 / 2 * 6 / cos 58 ( since tan 45 = 1)
= 3 sin 32 / cos 58
Note sine 32 = cos (90 - 32) = cos 58, so we have:
= 3 sin 32 / sin 32
= 3.
The possible values of x are 3 and 7
<h3>Solving rational expressions</h3>
Given the rational expression below;
√60-8x = x - 9
Square both sides to have:
(60-8x)² = (x-9)²
60-8x = x²-18x+81
Equate to zero to have;
x²-18x+81 - 60 + 8x = 0
x² - 10x + 21 = 0
x² -3x-7x +21 = 0
x(x-3)-7(x-3) = 0
x = 3 and 7
Hence the possible values of x are 3 and 7
Learn more on rational expression here: brainly.com/question/25292194
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Answer:
A) The factors are 5 & 6
B) There are 3 terms
C) the coefficient is 4
Step-by-step explanation:
I hope this helps <3
Answer:

Step-by-step explanation:
Anything to a negative power is pretty much,
(1 divided by (the whole exponet and with bae but the exponent is positive))
so i this case, it is 1/ 3^3
I'm assuming the syntax here is Javascript:
The str.substring() method takes in two integers - a start index and an end index - and returns all the characters in the specified range from the original string, <em>including</em> the character in the start index and <em>excluding </em>the character in the end index<em />. Javascript's is <em>0-indexed</em>, which means that all of its indices start at 0.
For instance, if we were to use the method on the string "test" and wanted to return the substring "tes", we'd call the following method:
"test".substring(0,3)
This would return everything from the first character, "t", <em>up to but not including</em> the fourth character, "t". The character immediately before the last "t" (index 3), "s" (index 2) would be our last character, and the console should print "tes" as a result.
For your example, "select".substring(4,4) prints out every character starting at index 4 - the fifth character, "c" - <em>up to but not including </em>the character at index 4. We start and stop at the same character, so the method will only return the character "c", and nothing else.