Answer:
1). t ≥ -
2). k ≥ 
3). y < -
4). b > 
5). w ≤ 0
Step-by-step explanation:
1). 
t ≥ -
2). 15k + 11 ≤ 18k - 5
15k - 18k ≤ -5 - 11
-3k ≤ - 16
3k ≥ 16
k ≥
3). 44y > 11 + 88y - 22y
44y > 11 + 66y
44y - 66y > 11
-22y > 11
22y < -11
y < 
4). 
(b - 27) > 
b > 
b >
5). 11w - 8w ≥ 14w
3w - 14w ≥ 0
-11w ≥ 0
w ≤ 0
0.08 divided by 1.44 is 0.055555556
Answer:
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Class 9
>>Maths
>>Quadrilaterals
>>Quadrilaterals and Their Various Types
>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
Question
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
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Medium
Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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<h3>Answer: Choice C</h3>
- domain = (-infinity, infinity)
- range = (-infinity, 0)
- horizontal asymptote is y = 0
========================================================
Explanation:
Since no division by zero errors are possible, and other domain restricting events are possible, we can plug in any x value we want. This means the domain is the set of all real numbers. Representing this in interval notation would be (-infinity, infinity).
The range is the set of negative real numbers, which when written in interval notation would be (-infinity, 0). This is because y = 5^x has a range of positive real numbers, and it flips when we negate the 5^x term. The graph of y = -5^x extends forever downward, and the upper limit is y = 0.
It never reaches y = 0 itself, so this is the horizontal asymptote. Think of it like an electric fence you can get closer to but can't touch.
24 dollars.
1/4 + 1/3 = 3/12 + 4/12 = 7/12
7/12 a + 8 = 22
7/12 a = 14
a = 14 x 12/7
a = 24 dollars
