Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
Answer:
1, 2, 4
Step-by-step explanation:
The triangles are similar by AAA or SSS (yes)
The sides are proportional (yes)
The length of AB is 21, not 15 (no)
The length of BC is 9 (yes)
The dilation is an enlargement, not reduction (no)
4x+8y=40
0.8*8=6.4
4x+6.4=40
40-6.4=33.6
4x=33.6
33.6\4=8.4
X=8.4
8ft is the dstance between them.
5+3 = 8
The first thing you should do is solve the equation yourself.
1) Distribute the 2.
6x + 4 = 2x – 16
2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
4x + 4 = -16
3) Now subtract 4 from both sides
4x + 4 – 4 = -16 – 4
4x = -12
4) Finally, divide both sides by 4
4x/4 = -12/4
x = –3
To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.
