Answer : 4 times
Here it's given that ,
- The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .
And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .
Let us take ,
- base of blue butterfly be b
- height of blue butterfly be h
- Area be A .
Then ,
- base of red butterfly will be 2b .
- height of red butterfly will be 2h .
- Area be A' .
We know that ,
→ area of the triangle = 1/2 × base × height
So that ,
→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)
→ A/A' = bh/4bh
→ A/A' = 1/4
→ A' = 4A
<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>
I hope this helps.
Answer:
Option A is correct
Step-by-step explanation:
For the box y=mx+c
Hope this helps
Answer:
He should sell them he would be rich.
Step-by-step explanation:
-2<em>x</em> + 6<em>y</em> = -38
3<em>x</em> - 4<em>y</em> = 32
To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.
3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114
2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64
Add the equations.
-6<em>x </em>+ 18<em>y</em> = -114
6<em>x</em> - 8<em>y</em> = 64
+_____________
0 + 10<em>y</em> = -50
10<em>y</em> = -50
<em>y</em> = -5
Substitute -5 for y into one of the original equations to find x.
3<em>x</em> - 4<em>y</em> = 32
3<em>x</em> - 4(-5) = 32
3<em>x</em> + 20 = 32
3<em>x</em> = 12
<em>x</em> = 4
Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.
-2<em>x</em> + 6<em>y</em> = -38
-2(4) + 6(-5) = -38
-8 - 30 = 38
38 = 38
3<em>x</em> - 4<em>y</em> = 32
3(4) - 4(-5) = 32
12 + 20 = 32
32 = 32
Answer:
<em>x</em> = 4 and <em>y</em> = -5; (4, -5).
