1. AB 3-2/-1-1
-1/2
BC 2+1/1+3
3/4
AC 3+1/-1+3
4/2=2
It is a right triangle
2. JK -1-2/4+3
-3/7
LM -2+5/-5-2
-3/7
KL -1+5/4-2
<u>4/2=2</u>
JM 2+2/-3+5
<u>4/2=2
</u><u />The quadrilateral is a parallelogram
First one:
cos(A)=AC/AB=3/4.24
cos(B)=BC/AB=3/4.24
Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1
Second one:
To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).
If that's the case, AE is a transversal of parallel lines AB and DE.
And Angle A is congruent to angle E (alternate interior angles).
Therefore sin(A)=sin(E)=0.5
7 34/24. Hope this helps!
Circle b:
Diameter = x
Radius =

Area =

Circle a:
Diameter =

Radius =

Area =

Thus,
Area of circle b to area of circle a
=

÷

=

×

= 4
Hence, the area of circle b is
4 times the area of circle a.
she has cancer, sorry but were gonna have to let kelly down