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Andrews [41]
3 years ago
14

In a cross between two heterozygous individuals (eg. Rr X Rr), the expected phenotypic ratio of the offspring would be A) 1:2:2:

1. B) 1:2:1. C) 1:1. D) 3:1.

Biology
2 answers:
geniusboy [140]3 years ago
7 0
3:1.<span> The physical appearance of the </span>offspring<span> will be 3 </span>organisms<span> that look like the </span>parents<span>: 1 individual that differs in appearance.</span>
slavikrds [6]3 years ago
4 0

In a cross between two heterozygous individuals (eg. Rr X Rr), the expected phenotypic ratio of the offspring would be 3:1.

Reason:

When we cross Rr X Rr

we get

RR Rr Rr rr

Since R is dominant over r, the individuals with genotype RR and Rr will have the dominant phenotype. This implies that 3 offsprings will have dominant phenotype and 1 offspring (rr) will have recessive phenotype.

Thus the phenotypic ratio will be 3:1.

The image for the Punnett cross displaying this cross is attached for a better understanding of how the cross is made.

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Which of the following best represents the relationship of the concentration of hydrogen ions between water, vinegar, and ammoni
aalyn [17]

Answer: The second image best represents the relationship of the concentration of hydrogen ions between water, vinegar and ammonia.

Explanation: pH is the measure of alkalinity and acidity of a substance in a logarithmic scale.

Mathematically,

pH=-\log[H^+]

The solutions which lie in the pH range of 0 - 6.9 are considered as acidic solutions and they have more hydrogen ion concentration.

The solution which has a pH value of 7 is considered as a neutral solution and this solution has same hydrogen and hydroxide ion concentration.

The solutions which lie in the pH range of 7.1 - 14 are considered as basic solutions and they have less hydrogen ion concentration.

  • For vinegar, the hydrogen ion concentration is very high.
  • For water, the hydrogen ion concentration will be equal to the hydroxide ion concentration.
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6 0
3 years ago
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Which of these statements correctly compares probeware (such as an electronic temperature probe) to traditional analog tools (su
otez555 [7]

The answer is letter D. <span>Probeware is useful for obtaining many measurements in rapid succession.
</span>>Probewares are used to <span>collect precise data in real-time and analyze the results with powerful tools fuels. It is easy to use and also cost-effective.</span><span>

Choices to this question are:
A) Measurements by traditional analog tools are good to a larger number of significant figures.
B) Measurements by traditional analog tools are less prone to experimental error.
C)  Probeware is typically very difficult to transport.
D ) Probeware is useful for obtaining many measurements in rapid succession.


</span>
3 0
2 years ago
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You have two pure substances that you cannot identify each sample is solid at room temperature describe at least five steps in t
lapo4ka [179]

Answer:

Explanation:

If we have two solid samples, in order to identify what they are a series of ordered steps have to be performed.

1) The first thing to do is to observe the sample. If there is color it <u>may indicate</u> the presence of certain anions: for example if the sample is purple, it can be because of the presence of the permanganate ion (MnO₄⁻), if it is yellow it can be chromate ion (CrO₄⁻), if it is orange it can be the dichromate Cr₂O₇²⁻), etcetera. If the color of the sample is white we have no indication whatsoever.

2) Then we can use certain reactants to precipitate the cations of the sample. For example, we can add first HCN 3N to our sample. If there is precipitation, it means that the cations Ag⁺ or Pb²⁺ are present. If not, there are other cations and we must use a different reactant to precipitate them.

3) We then add H₂S to the sample (not adding it per se, but generating it heating thioacetamide with water). If we see a black precipitate, it can be because of the cations Pb²⁺, Bi³⁺ or Cu²⁺. If we see a yellow precipitate, it corresponds to Cd²⁺. If we do not see a precipitate, we need to add other reactant.

4) We add NaOH to the sample. If we see precipitate, it can be because of the the ions Fe³⁺, Ni²⁺, Co²⁺ or Mn²⁺.

5) We observe the color of this precipitate. If it is brown is Fe(OH)₃, if it is green is Ni(OH)₂, if it is pink is Co(OH)₂, and if it is white is Mn(OH)₂.

Se toma la muestra problema o alícuota y se añade HCl 2N. Con este reactivo precipitan los cationes del Grupo I ( Plata (I), Plomo (II) y Mercurio (I)): AgCl, PbCl2 y Hg2Cl2. Sobre el mismo embudo se añade agua de ebullición, quedando en el papel de filtro el AgCl y el Hg2Cl2; el Pb2+ puede identificar añadiendo KI, que origina un precipitado de PbI2 que se disuelve en caliente, que sirve para identificarlo mediante la llamada lluvia de oro.1​

Sobre el mismo papel de filtro se añade NH3 2N. En el papel de filtro si existe Hg22+ y se forma una mancha blanca, gris o negro, que es una mezcla de HgClNH2 y Hg0. En la disolución se forman Ag(NH3)2+, que se puede identificar con KI dando un precipitado de AgI amarillo claro.

3 0
3 years ago
Which of the following statements correctly describes some aspect of ATP hydrolysis being used to drive the active transport of
saw5 [17]

Answer:

B) This is an example of energy coupling

Explanation:

Energy coupling is a process by which cells carry out thermodynamically unfavorable, endergonic (energy-requiring) reactions to other exergonic (reactions that liberate free energy) reactions.

Reactions which are endergonic do not occur spontaneously as they result in a decrease in entropy and a positive free energy change, ∆G.

Exergonic reactions occur spontaneously as they result in an increase in entropy and have a negative free energy change, ∆G.

For example, the active transport of ions against their concentration gradients in cells is a non-spontaneous endergonic process which is coupled to the hydrolysis of ATP, an exergonic process in other for the reaction to proceed. ATP hydrolysis phosphorylates an amino acid side chain in the transport protein which then drives the forward process of transport of the ion.

Considering the above,

Option A: The hydrolysis of ATP is endergonic, and the active transport is exergonic is false because ATP hydrolysis is exergonic while active transport is endergonic.

Option B: This is an example of energy coupling is true.

Option C: Both ATP hydrolysis and active transport are spontaneous because they result in an increase in entropy of the system is false because only ATP hydrolysis is spontaneous

Option D: Neither ATP hydrolysis nor active transport is spontaneous is false because ATP hydrolysis is spontaneous.

Option E: ATP is acting as a transport protein to facilitate the movement of the ion across the plasma membrane is false because ATP is not a protein, rather it serves to activate the transport protein by phosphorylating it.

8 0
2 years ago
When you talk together in a group during a laboratory exercise, you are engaging in public scientific communication. classroom s
egoroff_w [7]

Answer:

Option number 2 is correct. When you talk together in a group during a laboratory exercise, you are engaging in classroom scientific communication.

Explanation:

Any type of communication that is made regarding science is described as a scientific communication. This kind of communication generally involves talks about research, recent advances in any scientific topics or techniques, observations that one might have made on a particular science topic, asking another person about any science-related topic or techniques, etc.

If a scientist talks about any science topic to the public, then it would be a public scientific communication. A scientific communication made among scientists would be termed as professional scientific communication. Any science based communication that is made and kept private would be termed as private scientific communication.

Hence, option 2 is correct. A science based communication between students in a lab would be classroom scientific communication.

6 0
3 years ago
Read 2 more answers
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