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3 years ago

Can a five year old do Algebra? yes but how and why?

Mathematics

2 answers:

marishachu [46]3 years ago

8 0

Yes. But it highly unlikely you will find one that can do it. It will be rare

melamori03 [73]3 years ago

5 0

A five year old can do algebra. They can if they are one of those VERY rare children. By rare children I mean their brains can process work faster than others making them able to understand it yet being so young. Also maybe because they had learned quickly they had found a algebra book and started to self teach themselves how to do that. Because if a child has a strong mind and can grasp things and learn for themselves they can learn it from looking at complete problems. Then solve them. I have seen kids be able to do math like this at a young age because they were quick at grasping the information. Also it could be that they had copied a basic formula for algebra off of a website or math book and just put their numbers in and started solving it like that. Also it could just be that they had learned it form a parent or older sibling because they were smart enough they were able to already be learning. Finally it could just be that they are a mathematical genius and were able to complete things like that themselves.

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Bob works at a construction company. He has an equally likely chance to be assigned to work diffrent crews every day. He can be

Sergio [31]

The answer is 6 times

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4 years ago

Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81

Anton [14]

Using Lagrange multipliers, we have the Lagrangian

$L(x,y,z,\lambda)=x+y-z+\lambda(x^2+y^2+z^2-81)$

with partial derivatives (set equal to 0)

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$
$L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}$
$L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}$
$L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81$

Substituting the first three equations into the fourth allows us to solve for $\lambda$ :

$x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}$

For each possible value of $\lambda$ , we get two corresponding critical points at $(\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3)$ .

At these points, respectively, we get a maximum value of $f(3\sqrt3,3\sqrt3,-3\sqrt3)=9\sqrt3$ and a minimum value of $f(-3\sqrt3,-3\sqrt3,3\sqrt3)=-9\sqrt3$ .

5 0

3 years ago

The population of a town is increasing by 300 inhabitants each year. If its population at the beginning of 1990 was 21,152, what

babunello [35]

Answer:

Step-by-step explanation:

You take the starting year of 1990 and subtract it from 1999 to get the year span of 9,

You then take the amount per year the population goes up by which is 300, so 300 multiplied by 9 is 2,700

You add 2,700 to 21,152 to get B-23,852

8 0

4 years ago

Work out the value of a and b in the identity.<br> 3ax + 6 - 4(x + b)= 11x + 14

Levart [38]

Answer:

a=5, b=-2

Step-by-step explanation:

If you simplify the equation, you get:

3ax +6 -4x -4b - 11x - 14 = 0 =>

3ax - 15x -4b -8 = 0

group together x's and constants:

(3a-15)x -8 -4b = 0

To make this 0 for all x, we have to find an a such that 3a-15 = 0 and b such that -8-4b = 0. this leads to a=5, b=-2

5 0

3 years ago

I need answer for this question

just olya [345]

The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.

In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:

Z = X-ц / σ

· It measures how many standard deviations the measure is from the mean.

· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ

σ = σ / $\sqrt{n}$

σ is standard deviation

n is the sample size.

Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.

⇒ ц = 176.1 and σ = 35.4

For a sample of 43 passengers, we have

n = 43

σ = $\frac{35.4}{\sqrt{43}}$

σ = 5.398

Z = X-ц / σ

Z = $\frac{165-176.1}{5.398}$

Z = -2.05 has p- value of 0.9798

The probability that the aircraft is loaded is

1 - p-value of Z

1 - 0.0202 = 0.9798

The probability that the aircraft is overloaded is 97.98%

Know more about Normal probability Distribution: -brainly.com/question/9333901

#SPJ9

6 0

1 year ago