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4 years ago

How many circles have a center of (4,7)?

1 answer:

6 0

Any circle that can given by

$(x-4)^{2}+(y-7)^{2}=r^{2}$

have a center of $(4,\;7).$

You can choose any positive value for the radius $r.$ Hence, there are infinity circles.

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Can someone help me?!?

gladu [14]

Answer:d

Step-by-step explanation:he only gets charged 20 dollars every month and 2.50 per gigabyte so the 2.50 gets multiplyed by g

3 0

3 years ago

A television screen, length is 16 1/2 inches, width is w inches, and area is 462 square inches. Select all THREE equations that

tatiyna

Answer:

it's B, C, and D

Step-by-step explanation:

A. w ⋅ 462 = 16 1/2

not A

w * a ≠ l

B. 16 1/2 ⋅ w = 462

is B

l * w = a

C. 462 ÷ 16 1/2 = w

is C

a / l = w

D. 462 ÷ w = 16 1/2

is D

a / w = l

E. 16 1/2 ⋅ 462 = w

not E

l * a ≠ w

3 0

3 years ago

The function f(x) = -5x2 + 13x + 6 represents the height, in meters, of a

AnnZ [28]

Answer:

Step-by-step explanation:

Differentiate the function and set it to zero:

f'(x) = -10x + 13

0 = -10x + 13

x = 1.3 seconds

Plug the x value into f(x):

f(1.3) = -5(1.3)^2 + 13(1.3) + 6 = 14.45 meters

8 0

3 years ago

For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in

Rainbow [258]

Answer:

$\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

x₁ - 5x₂ + x₄ = 5

Matrix form

$\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}$ $\begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}$

Generally the echelon reduction is mathematically applied as

$\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}$

Add -2 times the 1st row to the 2nd row

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}$

Multiply the 2nd row by -1/8

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}$

Add -1 times the 2nd row to the 3rd row

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}$

Multiply the 3rd row by -8/41

$\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

$\begin{Vmatrix}1 & 3 & 0&49/41&165/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

Add -3 times the 2nd row to the 1st row

$\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}$

3 0

3 years ago

Need help po. Salamat

Ede4ka [16]

Answer:

1. y ≥ 100

2. y ≤ 300

3. y ≥ 20000

4. 2y ≥ 80

5. 2y ≤ 90

Step-by-step explanation:

Let y be the variable.

1. The discount is not less than 100.

If the discount (i.e y) is not less than 100, it means it is either 100 or greater than 100.

This can be written as:

y ≥ 100

2. The cost of the book is at most 300.

This implies that the cost of the book (i.e y) is either 300 or lesser.

This can be written as:

y ≤ 300

3. His monthly income is at least 20000. This simply means that his monthly income (i.e y) is 20000 or greater than 20000.

This can be written as:

y ≥ 20000

4. Twice the number is at least 80.

Let the number be y.

Twice the number y can be written as:

But twice the number is at least 80.

This means that twice the number is 80 or greater than 80. This can be written as:

2y ≥ 80

5. Twice the measure of the acute angle is not more than 90 degree.

Let the angle be y.

Twice the angle can be written as:

But twice the measure of the angle is not more than 90 degree. This implies that twice the angle is 90 or lesser than 90. This can be written as:

2y ≤ 90

6 0

3 years ago