We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
Answer:
68$ Is your answer
Step-by-step explanation:
Hope this helps
Answer:
-19
Step-by-step explanation:
After staring at this for a few seconds, I think the equation
![-5\sqrt{10}\cdot\sqrt{15}=[1]\sqrt{[2]}](https://tex.z-dn.net/?f=-5%5Csqrt%7B10%7D%5Ccdot%5Csqrt%7B15%7D%3D%5B1%5D%5Csqrt%7B%5B2%5D%7D)
is asking you to simplify the left hand side so that it has a form matching the right hand side, and [1] and [2] are placeholders. My guess is that they're supposed to be integers.
Notice that
Then multiplying by -5, we have
so I believe [1] = -25, and [2] = 6.
You would simply have to plug in, or substitute, the given values in the equations.
So, H=-5, W=2 and the problem is 4h-3w
To plug them in, your new equation would be 4(-5)-3(2) and simplify. So it becomes -20-6 which = -26.
And -26 would be your answer.
