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Fofino [41]
3 years ago
11

G^2 + 4gh; if g = -3 and h = 5

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

Step-by-step explanation:

We know that g = -3 and h = 5

Plugging in the values for g and h you will get:

g^{2} + 4gh

(-3)^{2} + 4(-3)(5)

9 + (-60)

Final answer is -51

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Step-by-step explanation:

According to the graph, the line's x-values span from negative infinity to infinity:

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7. Select each problem that has a quotient of 0.4*<br> 16 = 40<br> 24 = 6<br> 60 = 16<br> 3.6 - 9
mr Goodwill [35]
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8 0
3 years ago
I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t
belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}

Where

\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}

Thus,

\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}

thus, BC = 7.5

2) BX = 9, BA = 15, BY = 15, YC = y

In the above diagram,

\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}

Thus, from the theorem of similar triangles,

\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}

solving for y, we have

\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}

thus, YC = 10.

4 0
1 year ago
A parallelogram has sides 17.3 m and 43.4 m long. The height corresponding to the 17.3-m base is 8.7 m. Find the height, to the
Anvisha [2.4K]

Answer:

3.5m

Step-by-step explanation:

A parallelogram has sides 17.3 m and 43.4 m long.

The height corresponding to the 17.3-m base is 8.7 m.

The area of a parallelogram = base × height

= 8.7m × 17.3m

= 150.51m²

Both parallelograms have the same area

Hence, the height, to the nearest tenth of a meter, corresponding to the 43.4-m base is calculated as:

= 150.51m²/43.4m

= 3.4679723502m

Approximately = 3.5m

7 0
3 years ago
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