Answer:
14 units is the answer :)
Step-by-step explanation:
The first option is correct.
Moving 1.5 units to the left (or -1.5 units to the right).
Moving 1 unit down (or -1 unit up).
Therefore you get the result of (-1.5, 1) as is the location of the rink.
Answer:
6 cm
Step-by-step explanation:
If the original side length is x, then the modified square has an area of ...
A = LW
32 = (x +2)(x -2) = x^2 -4
36 = x^2 . . . . . . . . add 4
6 = x . . . . . . . . . . take the square root
The original figure has a side length of 6 cm.
__
<em>Check</em>
The modified figure is 8 cm by 4 cm = 32 cm^2.
So the equation for these types of equations is f(x) = a(x-h)+k with h being a horizontal translation, a being a stretch/compression and k being a vertical translation. So here if you want a stretch of 4 a would be four, g(x)=4(-3x-h)+k. Also, there is a horizontal translation so it would be positive 4 into the equation. Since there is no change in the y-axis there is no vertical translation resulting in g(x) = 4(-3x-4)
