Answer:
50% change in volume
Step-by-step explanation:
<h2>
This problem bothers on the mensuration of solid shapes.</h2>
In this problem we are to find the volume of the first cylinder and compare with the second cylinder.
Given data
Volume v = ?
Diameter d=
?
Radius r = 
Height h= 
we know that the volume of a cylinder is expressed as
Substituting our given data we have
The first cylinder as a volume of 
The change in volume is 
percentage = 
%
The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
