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timurjin [86]
3 years ago
9

SIMPLE PROBABILITY what did i do wrong?(the answer in read is the correct answer)

Mathematics
1 answer:
Triss [41]3 years ago
4 0

Answer:

The answer is x = 97*192000/600 = 31040

Step-by-step explanation:

Because \frac{x}{192000} =\frac{97}{600}

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HELPPP
alina1380 [7]
Ok, So:

10x3=30-3=27

It Would Be 27
6 0
3 years ago
Read 2 more answers
If the base of a square pyramid is 9 centimeters, and it has a volume of 324 cubic centimeters, what is the height of the pyrami
masha68 [24]

A

The volume (V) of a pyramid is found using the formula

V = \frac{1}{3} × area of base × height(h)

area of base = 9² = 81 ← area of a square, hence

324 = \frac{1}{3} × 81 × h = 27h ( divide both sides by 27 )

h = \frac{324}{27} = 12 → A



3 0
3 years ago
Can anybody help me???​
Tasya [4]

#10

\\ \rm\longmapsto 0

#11

  • Last three i.e Option B,C,D

#13

It started from negative ends at positive hence

\\ \rm\longmapsto y=-|x|+2

#14

  • (-3,-10)

\\ \rm\longmapsto 2(-3)-(-10)=4

\\ \rm\longmapsto -6+10=4

  • Proved

#15

  • (1,1)

\\ \rm\longmapsto 1=(1-2)^2=(-1)^2=1

#16

  • (2,-4)

\\ \rm\longmapsto -2-2(-4)>3

\\ \rm\longmapsto -2+8>3

\\ \rm\longmapsto 6>3

5 0
3 years ago
Determine if the two figures are congruent and explain your answer using transformations.
Maslowich

The coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent

  • The given figures are quadrilaterals, in order to determine whether they are similar, we need to check if they are reflections of each other.

  • For the Quadrilateral ABCD, the coordinate of A is at A(-1, 1)  and for the Quadrilateral DEFG, the coordinate of E is at E(1, 1).

  • Note that if an object is reflected over the y-axis the transformation is (x, y)->(-x, y)

  • We need to check whether if we reflect the coordinate A over the y-axis we will get coordinate E

Since the coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent

Learn more on reflections here:brainly.com/question/1908648

7 0
2 years ago
Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen
harina [27]

The matrix

A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}

has eigenvalues \lambda such that

\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0

(\cos\theta-\lambda)^2+\sin^2\theta=0

(\cos\theta-\lambda)^2=-\sin^2\theta

\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}

\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}

\sin^2\theta\ge0 for all values of \theta, so we need to have \sin\theta=0 in order for \lambda to be real-valued. This happens for

\sin\theta=0\implies\theta=n\pi

where n is any integer, and over the given interval we have \theta=0 and \theta=\pi.

4 0
3 years ago
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