Question

Including all coefficients, charges, and phases, what is the correct net ionic equation for the following set of reactants? Assume that the contribution of protons from H2SO4 is near 100% . Ba(OH)2(aq)+H2SO4(aq)
Express your answer as a chemical equation.

Answer 1

The correct net ionic equation for the chemical equation involving the reactants Ba(OH)2(aq) and H2SO4(aq) is  Ba²⁺ (aq) + 2OH⁻ (aq) + 2H⁺(aq) + SO4²⁻ (aq) --> BaSO₄(s) + H₂O(l)

Further Explanation

The chemical reaction between Ba(OH)2(aq) and H2SO4(aq) will be given by;

Ba(OH)₂(aq) + H₂SO4(aq) --> BaSO₄(aq) + 2H₂O(l)

Net ionic equations  

• Net ionic equations that do not include all ions that are present in the reactants and products.
• The equations only includes the ions that are involved in the reaction.

• The ions that are not involved in a chemical reaction are called spectator ions and are cancelled out while writing ionic equations.
• Reaction between Ba(OH)2(aq) and H2SO4(aq is an example of a neutralization reaction or a double displacement reaction.
• During the reaction Barium ion bonds with sulfate ions and forms barium sulfate which is a solid, while hydrogen ion bonds with hydroxide ion to form water which is a liquid

That is:  

Ba(OH)₂(aq) + H₂SO4(aq) --> BaSO₄(s) + 2H₂O(l)

• Barium ion changes from aqueous to solid state barium sulfate there it is an ion involved in the reaction.
• Additionally, all the other ions are also involved in the reaction since they have changed their initial state. The chemical reaction has no spectator ions.

Therefore; the ionic equation required will be;  

Ba²⁺ (aq) + 2OH⁻ (aq) + 2H⁺(aq) + SO4²⁻ (aq) --> BaSO₄(s) + H₂O(l)

Keywords: Net ionic equations

Learn more about;  

• Net ionic equation: brainly.com/question/5552670
• Spectator ions: brainly.com/question/5552670
• Example of net ionic equations:  brainly.com/question/5552670

Level: High school

Subject: Chemistry

Topic: Chemical equation

Sub-topic: Net ionic equations

Answer 2

The correct ionic equation that includes all the charges, phases, and coefficients is as follows:

$\boxed{{\text{B}}{{\text{a}}^{2+}}\left({aq}\right)+2{\text{O}}{{\text{H}}^-}\left({aq}\right)+2{{\text{H}}^+}\left({aq}\right)+{\text{S}}{{\text{O}}_4}^{2-}\left({aq}\right)\to{\text{BaS}}{{\text{O}}_4}\left(s\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(s\right)}$

Further explanation:

Double displacement reaction is defined as the reaction in which ions of two compound interchange with each other to form the product. For example, the general double displacement reaction between two compounds ${\text{AX}}$ and ${\text{BY}}$ is as follows:

${\text{AX}}+{\text{BY}}\to{\text{AY}}+{\text{BX}}$

The three types of equations that are employed to represent the chemical reaction are as follows:

1. Molecular equation

2. Total ionic equation

3. Net ionic equation

The molecular equation represents the reactants and products of the ionic reaction in dissociated form. In total ionic reaction, all the dissociated ions that are present in the reaction mixture are represented and in net ionic reaction, the useful ions that participate in the reaction are represented.

In first step, write the molecular equation for the reaction with the phases in bracket.

${\text{Ba}}{\left({{\text{OH}}}\right)_2}\left({aq}\right)+{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)\to{\text{BaS}}{{\text{O}}_4}\left(s\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(l\right)$

Note that parentheses indicate the state or the phase of the compound.  

In second step, dissociate all the compounds with aqueous phase to write the total ionic equation and then cancel out the common ions on both sides to get the net ionic equation. The compounds with solid phase remain same.

The ionic species present in ${\text{Ba}}{\left({{\text{OH}}}\right)_2}$is ${\text{B}}{{\text{a}}^{2+}}$and ${\text{O}}{{\text{H}}^-}$ respectively. Similarly, the ionic species in ${{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_4}$is $2{{\text{H}}^+}$and  ${\text{S}}{{\text{O}}_4}^{2-}$respectively. Hence the net ionic equation can be represented as follows:

${\text{B}}{{\text{a}}^{2+}}\left({aq}\right)+2{\text{O}}{{\text{H}}^-}\left({aq}\right)+2{{\text{H}}^+}\left({aq}\right)+{\text{S}}{{\text{O}}_4}^{2-}\left({aq}\right)\to{\text{BaS}}{{\text{O}}_4}\left(s\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(l\right)$

Learn more:

1. Component of John Dalton’s atomic theory:brainly.com/question/2357175

2. Identification of all of the phases of the reaction: brainly.com/question/8926688

Answer details:

Grade: High school

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Chemical equation, Law of conservation of mass, phase, double displacement reactions, ionic equation, BaSO4, H2SO4.