Which electron configuration represents the electrons of an atom of neon in an excited state?
2 answers:
Answer: Option (C) is the correct answer.
Explanation:
Atomic number of neon is 10 and its electronic configuration is .
As neon has a vacant 3s orbital also. Therefore, in the excited state an electron will jump into the excited energy level. So, in excited state of neon one electron will jump into the 3s orbital.
Hence, its electronic distribution in the valence shell will become 2-7-1.
Thus, we can conclude that 2-7-1 electron configuration represents the electrons of an atom of neon in an excited state.
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Answer:
As the specific heat capacity for pure diamond is 0.5091 and it is different from the specific heat capacity found that is 0.2699
, the diamond sample is not pure.
Explanation:
1. As the problem says the equation that describes the amount of heat gained or lost by a substance is:
q=Cp*m*ΔT
where q is the amount of heat, Cp is the specific heat capacity, m is the mass and ΔT is the change in the temperature.
2. Solving for specific heat capacity:
3. Replacing values:
As the specific heat capacity for pure diamond is 0.5091 and it is different from the specific heat capacity found that is 0.2699
, the diamond sample is not pure.