Answer:
71820 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 1.05 Kg
Initial Temperature (T₁) = 23 °C
Final temperature (T₂) = 99 °C
Heat (Q) required =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial Temperature (T₁) = 23 °C
Final temperature (T₂) = 99 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 99 – 23
ΔT = 76 °C
Finally, we shall determine the heat required. This can be obtained as follow:
Mass (M) = 1.05 Kg
Change in temperature (ΔT) = 76 °C
Specific heat capacity (C) of aluminum = 900 J/KgºC
Heat (Q) required =?
Q = MCΔT
Q = 1.05 × 900 × 76
Q = 71820 J
Thus, 71820 J heat energy is required.
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Water Solution
Because you are testing the water solutions pH
Answer:
89%
Explanation:
The computation of the sample percentage is sugar is shown below:
As we know that
The mass of the total sample mixture is
= Mass of salt + mass of sugar
= 0.8920
And, the mass of salt is 0.0982 g
So, the mass of sugar is
= 0.8920 - 0.0982
= 0.7938 g
Now the percentage of the sample is sugar is
= 0.7938 ÷ 0.8920
= 89%