Answer:
<h3>
97, 485 and 197</h3>
Step-by-step explanation:
x - the first number
One number is 5 times a first number:
5x - "one" number (the second number)
A third number is 100 more than the first number:
x + 100 - the third number
x + 5x + x+100 - the sum of the three numbers
x + 5x + x+100 = 779
-100 -100
7x = 679
÷7 ÷7
x = 97
5x = 5•97 = 485
x+100 = 97 + 100 = 197
Check:
97 + 485 + 197 = 779
1, 4, 13, 40, 121, 364, 1,093, 3,280, 9,841, 29,524, 88,573.
Hoped this helped :)
√((x^6)/(y^4))
x^6 indicates x to the sixth power, the same goes for y^4.
Let the necessary amount of water be x. Then (1.00)(1 gallon antifreeze) = 0.40(x+1 gallon), or 1 = .40x + .40. Combining like terms: 0.60 = 0.40x.
Then x = 0.60 / 0.40 = 1.5.
Adding 1.5 gallons of water to that 1 gallon of pure antifreeze results in 2.5 gallons of 40% antifreeze.
Answer: choice B
Angle A = 63 degrees
side a = 13.4
side b = 6.8
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Given Info:
Angle C = 90 degrees
Angle B = 27 degrees
side c = 15
What is needed to be found:
Angle A, side a, side b
Finding side a
cos(angle) = adjacent/hypotenuse
cos(B) = BC/AB
cos(B) = a/15
cos(27) = a/15
15*cos(27) = a
13.3650978628256 = a
a = 13.3650978628256
a = 13.4
Finding side b
Using the pythagorean theorem
a^2 + b^2 = c^2
(13.3650978628256)^2 + b^2 = 15^2
178.625840882906 + b^2 = 225
178.625840882906 + b^2 - 178.625840882906 = 225 - 178.625840882906
b^2 = 46.374159117094
sqrt(b^2) = sqrt(46.374159117094)
b = 6.809857496093
b = 6.8
Finding angle A
sin(angle) = opposite/hypotenuse
sin(A) = BC/AB
sin(A) = a/c
sin(A) = 13.3650978628256/15
sin(A) = 0.89100652418838
arcsin(sin(A)) = arcsin(0.89100652418838)
A = 63.0000000000016
A = 63
