Answer:
JUST USE THE PROPERTIES OF MULT, ADD, SUBT, AND DIV.
Step-by-step explanation:
Answer:
It is not a subspace.
Step-by-step explanation:
So, the polynomial degree of at most 3 is given below as;
V = { p (z) = b0 + b1z + b2z^ + ... + bnz^n. |n is less than or equal to 3 and b0, b1, b2,... are integers.
To determine whether a subset is a subspace of Pn, we have to check for the properties below;
(1). Zero vector property : that is, when polynomial, p(z) = 0 and 0 is an integer.
(2). Addition property= here, we have; p(z) + h(z) = (b0 + b1z + b2z^2 +....+ bnz^n) + ( c0 + c1z + c^2z^2 +... + cnz^n). That is the sum of integers.
(3). Scaler multiplication property: the coefficient here may not be real numbers therefore, the condition is not followed here.
Therefore, it is not a subspace of Pn.
Answer:
5x+9
Step-by-step explanation:
How many boxes? and what was the question?
Answer:
-35,35,0
Step-by-step explanation:
Let's organise our information :
Now let's add them together :
- x+xy²+x-xy²=250y-240y
- 2x=10y
- x=5y ⇒ y= x/5
Let's replace y by x/5 in the first equation :
- x+x*(x/5)²=250*(x/5)
- x+ (x∧3)/25 = 50x
- 49x-(x∧3)/25=0
- x(49-(x²/25))=0
- x=0 or 49-(x²/25)=0
- x=0 or 49= x²/25
- x=0 or x²=1225
- x=0 or x= or x= -
- x=0 or x=35 or x= -35
so x=[0,35,(-35)]