Evaluate 1/4c + 3d when c = 6 and d = 7

Mathematics

2 answers:

Natalka [10]3 years ago

7 0

Replace the C and D with 6 and 7.

1/4 (6) + 3 (7)

6/4 + 21

6/4 + 84/4 = 90/4

90/4 = 22.5

Hope this helps!

Lesechka [4]3 years ago

3 0

1/4(6) + 3(7)
= 1/4 x 6 + 3 x 7
1/4 x 6= 3/2
3 x 7= 21
= 3/2 +21
= 21/1 + 3/2
= 21 x 2/2 + 3/2
=2 x 21 + 3/2
= 45/2

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What is the value of |n|=5

nikdorinn [45]

Answer:

n = 5 or -5

Step-by-step explanation:

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3 years ago

Read 2 more answers

The access code for a garage door consists of three digits. Each digit can be any number from 1 through 5, and each digit can b

Papessa [141]

Answer:

(a) 125

$(b) \dfrac{1}{125}$

$(c) \dfrac{124}{125}$

Step-by-step explanation:

We are given that access code consists of 3 digits.

Each digit can be any digit through 1 to 5 and can be repeated.

Now, this problem is equivalent to the problem that we have to find:

The number of 3 digit numbers that can be formed using the digits 1 to 5 with repetition allowed.

(a) We have 3 places here, unit's, ten's and hundred's places respectively and each of the 3 places have 5 possibilities (any digit allowed with repetition).

So, total number of access codes possible:

$5\times 5 \times 5 = 125$

(b) Suppose, an access code is randomly selected, what is the probability that it will be correct.

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, only 1 code is correct, so

Number of favorable cases = 1

Total number of cases = 125

So, required probability:

$P(E) = \dfrac{1}{125}$

$P(\overline E) = 1-P(E)\\\Rightarrow P(\overline E) = 1-\dfrac{1}{125}\\\Rightarrow P(\overline E) = \dfrac{125-1}{125}\\\Rightarrow P(\overline E) = \dfrac{124}{125}$