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3 years ago

Evaluate 1/4c + 3d when c = 6 and d = 7

Mathematics

2 answers:

Natalka [10]3 years ago

7 0

Replace the C and D with 6 and 7.

1/4 (6) + 3 (7)

6/4 + 21

6/4 + 84/4 = 90/4

90/4 = 22.5

Hope this helps!

Lesechka [4]3 years ago

3 0

1/4(6) + 3(7)
= 1/4 x 6 + 3 x 7
1/4 x 6= 3/2
3 x 7= 21
= 3/2 +21
= 21/1 + 3/2
= 21 x 2/2 + 3/2
=2 x 21 + 3/2
= 45/2

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Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

Solution:

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

Alex is 12 years older than George

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

Carl is Three times older than Alex

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

The sum of their ages is 68

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

Substitute eqn 1 and eqn 2 in eqn 3

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

Substitute a = 16 in eqn 2

c = 3(16) = 48

c = 48

Substitute a = 16 in eqn 1

g = 16 - 12 = 4

g = 4

Find the ratio of George’s age to Carl’s age to Alex’s age

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

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Solve the equation 2p/3-12=-2

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$\frac{2p}{3} - 12 = -2$

Firstly, we are going add $12$ on each of the sides that we're working with. like ↓

$p - 12 + 12 \\ \\ = -2 + 12$

This gives us $\frac{2}{3}p = 10$ (if you are wondering how we got the out come of $10$ it is because I added $-2 + 12 = 10$

Now multiply $\frac{3}{2}$ on each of your sides

$\frac{3}{2} ( \frac{2}{3}p) \\ \\ = \frac{3}{2} (10)$

Cancel the first set and you will find the value of $p$

$p = 15$

Good luck on your assignment and enjoy your day

~ $LoveYourselfFirst:)$

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