I need this problem to be simplified
2 answers:
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The randomly selected subject is given bone density test which are normally distributed with mean =0 and standard deviation =1. It means bone density test score is standard normal variable.
The probability that a given score is less than 2.23
P(z < 2.23)
Using z score table to find probability below z=2.23
P(z < 2.23) = 0.9871
The probability that a given score is less than 2.23 is 0.9871
The complete question in the attached figure
we know that
in the larger box there are----------> 2*3*4-----> 24 cereal boxes
then
if 1 cereal boxes is---------------> 175 in³
24 cereal boxes----------------> X
X=24*175-------> x=4200 in³
the answer is
<span>the approximate volume of the larger box is 4200 in</span>³
we know that
in the larger box there are----------> 2*3*4-----> 24 cereal boxes
then
if 1 cereal boxes is---------------> 175 in³
24 cereal boxes----------------> X
X=24*175-------> x=4200 in³
the answer is
<span>the approximate volume of the larger box is 4200 in</span>³