First, we are going to find the vertex of our quadratic. Remember that to find the vertex

of a quadratic equation of the form

, we use the vertex formula

, and then, we evaluate our equation at

to find

.
We now from our quadratic that

and

, so lets use our formula:




Now we can evaluate our quadratic at 8 to find

:




So the vertex of our function is (8,-72)
Next, we are going to use the vertex to rewrite our quadratic equation:



The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.
We can conclude that:
The rewritten equation is

The x-coordinate of the minimum is 8
Ty=x 9
Malcolm=x+2 11
fred=2x+4 22
x+x+2+2x+4=42
4x+6=42
-6 -6
4x=36
36÷4
x=9
The answer for the question shown above is the second one, which is: The domain is all real numbers. The range is all real numbers greater than zero.
The explanation is shown below:
You have the following function given in the problem above f(x)= (1/5)^x. As you can see, it is a exponential function. By definition, the domain of the exponential functions is all the real numbers anf their range is all real numbers greater that zero.
You have to be a member for three months for both clubs to have the same cost
Answer:
4 is D
5 is B
Step-by-step explanation:
for #4 just plug the numbers into the formula: y = mx + b
for #5 use the slope formula.