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Natali5045456 [20]
2 years ago
15

A total of 200 10-year-old children of similar intellectual abilities participated in a noise experiment in their classrooms. Th

ey were tested for their ability to recall the meaning of a symbol in a textbook one week after the start of the experiment. Students did not know the meaning of the symbol prior to the experiment. The 200 students were split into 10 groups of 20 students and were taught the meaning of the symbol during a 15-minute lesson. Five groups learned the meaning of the symbol without any noise pollution outside of their classrooms. The other five groups learned the meaning of the symbol with a noise source of 55 decibels outside their classrooms, maintained continuously for the 15-minute lesson. One week after the lesson, 80% of the students who were not exposed to the noise sources were able to successfully recall the meaning of the symbol and 25% of the students exposed to the noise sources were able to successfully recall the meaning of the symbol. i. Identify the dependent variable in the experiment.
Mathematics
1 answer:
Vladimir79 [104]2 years ago
6 0

Answer:

The dependent variable for this experiment is the ability of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment which depends on the presence or absence of noise outside the classroom.

Step-by-step explanation:

In an experiment, the independent variable is the one whose value, form or outcome is not determined by any other variable in the experiment.

The dependent variable is the one whose value, form or outcome is determined by one or more other variable(s) in the experiment.

This experiment tests the abilities of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment.

This ability was made to depend on whether there was noise or no noise outside their classrooms.

Since, this variable to be measured is determined by another variable in the experiment, it is evident that this is the dependent variable for this experiment.

Hope this Helps!!!

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(Law of Sines)
Mariana [72]

Answer:

Option (D) is correct.

Step-by-step explanation:

In a triangle BCD , with b, c, d as the sides of triangle.

Sine rule states when we we divide side b by the sine of angle B then it is equal to side c divided by the sine of angle C and also equal to side d divided by the sine of angle D.

Using Sine rule,

\frac{b}{\sin B}=\frac{c}{\sin C}=\frac{d}{\sin D}

Consider the first and third ratio,

\frac{b}{\sin B}=\frac{d}{\sin D}

Substitute the values of d = 3 , b= 5 and ∠D=25°

\Rightarrow \frac{5}{\sin B}=\frac{3}{\sin 25^{\circ}}

\Rightarrow \sin B=\frac{\sin 25^{\circ} \times 5}{3}}  

 \Rightarrow \sin B=45,135

Thus, Measure of angle B is 45 and 135 as sinB is positive is first and 2nd quadrant.

Thus, option (D) is correct.


7 0
3 years ago
Read 2 more answers
Which of the following is the number of sides for a regular polygon that will not form a regular tessellation?
trasher [3.6K]

Answer with explanation:

A regular polygon is simple closed geometrical shape, only made up of line segments.

And Regular Tessellation, is geometrical shape, made up of regular polygons having, 3 ,or 4 or 6 sides.

It is combination of, only single kind of polygon,either, polygon having 3 sides, or ,4 sides or 6 sides.

→Regular polygon having 3 sides is Called Equilateral Triangle.

→Regular polygon having 4 sides is Called Square.

→Regular polygon having 6 sides is Called Regular Hexagon.

⇒Regular polygon having , 8 sides will not form a regular tessellation.

Option D

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3 years ago
Javier’s Bakery sells donuts in packages of 3 and cookies in packages of 5 today the backers sold the same number of donuts and
tekilochka [14]

The answer is A.) 5 because it’s the smaller number

8 0
2 years ago
Two landscapers must mow a rectangular lawn that measures 100 feet by 200 feet. Each wants to mow no more than half of the lawn.
Citrus2011 [14]

The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
One half of the lawn is  10,000 ft².  That's the limit that the first man
must be careful not to exceed, lest he blindly mow a couple of blades
more than his partner does, and become the laughing stock of the whole
company when the word gets around.  10,000 ft² ... no mas !

When you think about it ... massage it and roll it around in your
mind's eye, and then soon give up and make yourself a sketch ...
you realize that if he starts along the length of the field, then with
a 2-ft cut, the lengths of the strips he cuts will line up like this:

First lap:
       (200 - 0) = 200
       (100 - 2) = 98
       (200 - 2) = 198
       (100 - 4) = 96    

Second lap:
       (200 - 4) = 196
       (100 - 6) = 94
       (200 - 6) = 194
       (100 - 8) = 92   

Third lap:
       (200 - 8) = 192
       (100 - 10) = 90
       (200 - 10) = 190
       (100 - 12) = 88 

These are the lengths of each strip.  They're 2-ft wide, so the area
of each one is (2 x the length). 

I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it.  So I'll just keep going for another
lap, then add up all the areas and see how close he is:

Fourth lap:
       (200 - 12) = 188
       (100 - 14) = 86
       (200 - 14) = 186
       (100 - 16) = 84 

So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft².  If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.

Hey ! Maybe that's the key to the approximate pattern !

Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice.  (Approximately.)  So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.

So now we have rectangles measuring

         (200 x 100),  (196 x 96),  (192 x 92),  (188 x 88),  (184 x 84) ... etc.

and the areas of their rectangular strips are
           1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.

==> I see that the areas are decreasing by 32-ft² each lap.
       So the next few laps are 
               1040-ft², 1008-ft², 976-ft², 944-ft², 912-ft² ... etc. 

How much area do we have now:

             After 9 laps,    Area =   9,648-ft²
             After 10 laps,  Area = 10,560-ft².

And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
the total becomes 10,000-ft².   


There must still be an easier way to do it.  For now, however, I'll leave it
there, and go with my answer of:  During the 10th lap.

5 0
2 years ago
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