Question

Brian is solving the equation x^2 - 3/4x = 5. What value must be added to both sides of the equation to make the left side a perfect-square trinomial?

Answer 1

Answer:

The value that must be added to both sides of the equation is 9/64

Step-by-step explanation:

we have

$x^{2} -\frac{3}{4}x=5$

Divide the term -3/4 by 2

$\frac{(-3/4)}{2}=-\frac{3}{8}$

squared the term (-3/8)

$(-\frac{3}{8})^{2}=\frac{9}{64}$

Adds the term 9/64 both sides of the equation

$x^{2} -\frac{3}{4}x+\frac{9}{64}=5+\frac{9}{64}$

Rewrite as perfect square

$(x-\frac{3}{8})^{2}=\frac{329}{64}$

therefore

The value that must be added to both sides of the equation is 9/64