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Kruka [31]
3 years ago
12

I neeed help , can somebody please tell the answer . ?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
8 0

Answer:

x=39 degrees

Step-by-step explanation:

28+33+x=100

61+x=100

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Find the area of the shaded region Gh= 13yd
Feliz [49]

Answer:

area ≈ 344. 93 yard²

Step-by-step explanation:

The question you are asking is a circle with shaded portion and a portion not shaded  . The radius of the circle is given as 13 yards . H is the center of the circle and unshaded part of the the sector has an angle of 126°.

The area of a sector = ∅/360 × πr²

The other angle of the shaded  portion is unknown . To find the angle we subtract 126° from 360°(complete angle).

360 - 126 = 234°

area of a sector = ∅/360 × πr²

where

∅ = 234°

r = 13 yards

area =  234/360 × π × 13²

area = 234/360 × π × 169

area = 39546π/360

area = 109.85π

area = 109.85 × 3.14

area  of the shaded part = 344.929  yard²

nearest hundred will be

area ≈ 344. 93 yard²

4 0
3 years ago
Which fraction is equivalent to 0.3636?
deff fn [24]
The answer is0.4/1.0.good luck
3 0
3 years ago
What is the answer to this??
Helga [31]

Since the triangle is equilateral, all its angles are equal to 60°

AO is the bisector⇒∠OAD = 30°

AO AO is the hypotenuse, ∠OAD = 30°⇒

OD=10:2=5ft

By the Pythagorean theorem

10^2=AD^2+5^2\\AD=\sqrt{100-25} \\AD=\sqrt{75}

AC=AD+DC=2\sqrt{75}=10\sqrt{3}

S=\frac{a^2\sqrt{3} }{4}

S=\frac{(10\sqrt{3})^2\sqrt{3}  }{4} =\frac{300\sqrt{3} }{4} =75\sqrt{3} ft^2

Answer: A) S=75\sqrt{3}ft²

P.S. Hello from Russia and sorry for my bad english :^)

5 0
4 years ago
Write a related addition equation for the subtraction equation.
Bess [88]

Answer:

-7+12 will also give u 5 with a positive sign

8 0
3 years ago
True or False, Intrusive rocks have large crystals?
Sladkaya [172]
<h2>Answer:</h2>

<h3>True</h3>

<h2>Step-by-step explanation:</h2>

<h3>Intrusive rocks, have large crystals that are usually visible without a microscope. </h3>

<h2>Therefore it's true. </h2>

<h2>Hope it help you </h2>
4 0
3 years ago
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