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Yakvenalex [24]
3 years ago
12

Find a vector parametrization of the ellipse centered at the origin in the xy-plane that has major diameter 8 along the x-axis,

minor diameter 4 along the y-axis, and is oriented counter-clockwise. Your parametrization should make the point (4,0) correspond to t=0. Use t as the parameter in your answer.
Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

E(t) = [ 4cos(t) , 2 sin(t) ]

Step-by-step explanation:

The elipse ecuacion is of the form:

 (x² ÷ a² ) + (y² ÷ b² ) = 1    Where a and b are the horizontal and vertical semi-diameters respectively

In our particular case    x²/16 + y²/ 4 = 1

That form suggests  (x/a)² + (y/b)² =1            

And again in our case    x²/16  + y²/4 = 1                                                       the same shape of                 sin²α +cos²α = 1

So we call x = 4 cos(t )   and the

We need to find y        

x²/16  + y²/4 = 1  

x²/16  + y²/4 = 1   ⇒    (x²  +  4y²) ÷ 16  = 1

Solving for y     (x²  +  4y²)  = 16      ⇒  y²  = ( 16 - x²) ÷4

as   x = 4 cos(t)   ⇒  y²  =  (16 - 16cos²(t)) ÷ 4     y = √4 (1 -cos²(t)

y = 2 sin (t)

So the vector parametrization of the elipse is

E(t) = [ 4cos(t) , 2 sin(t) ]

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<u>Step-by-step explanation:</u>

It is given that,

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(a) The enrollment data is a population
(b) <span><span>Mean: 22,150.62
</span><span>(c) Median: 18,670
</span><span>(d) Range: 57,776
(e) Standard Deviation: </span></span><span>14,258.49

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(a) As we noticed in the problem, the enrollment data is used for the study of the number of enrollments in all of the public universities in Ohio. Since the given enrollment data contains the number of enrollments in all of the public univeristies in Ohio, the enrollment data is a population.

(b) To compute the mean, we get the sum of all the data points and divide it by the number of data points.

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Sum of all data points = </span><span> 1725 + 4344 + 14655 + 15693 + 17338 + 18641 18670 + 20251 + 20839 + 25612 + 34187 + 36502 </span> +<span>  <span>59,501
</span></span>Sum of all data points = <span> <span> 287,958

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mean = </span></span>287,958 ÷ 13 = <span> <span> 22,150.62

(c) The median is computed when the data points are arranged from least to greatest and it is equal to either:

>> the middle number - if the number of data points is an odd number, or</span></span>
>> the average of 2 middle numbers - if the number of data points is an even number

In the enrollment data, when the data points are arranged from lowest to highest, the following is the result:

1725, 4344, 14655, 15693, 17338, 18641, 18670, 20251, 20839, 25612, 34187, 36502, 59,501

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Hence, the median is 18670.

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Sum of the squares of data points </span></span>=  1725² + 4344² + 14655² + 15693² + 17338² + 18641² + 18670² + 20251² + 20839² + 25612² + 34187² + 36502²  +  59,501² 

Sum of the squares of data points = <span> <span> 9,021,404,700 
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