Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:
$400 and $1,000
Step-by-step explanation:
Let us assume the x be the amount invested in 7% account
And, 600 + x be the amount invested in 9% account
Now the equation is
7x% + 9%(600 + x) = $118
0.07x + 54 + 0.09x = $118
0.16x = $118 -$54
0.16x = $64
x = $400
And, the other one is = $400 + $600 = $1,000
The absolute value of the number plotted on the number line is; 0.5
<h3>How to find Absolute Value?</h3>
The absolute value (or modulus) | x | of a real number x is the non-negative value of x without regard to its sign. For example, the absolute value of 5 is 5, and the absolute value of −5 is also 5. The absolute value of a number may be thought of as its distance from zero along real number line
Thus, if 0.5 is marked on the number line, from the given options, we can say that if we apply the definition above that |0.5| = 0.5
Read more about Absolute Value at; brainly.com/question/24368848
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