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Zinaida [17]
2 years ago
8

A zookeeper weighed an African elephant to be 9 × 103 pounds and an African lion to be 4 × 102 pounds. How many times greater is

the weight of the elephant than the weight of the lion?
Mathematics
2 answers:
love history [14]2 years ago
6 0

Answer:

for people who use time4learning:

the answer is (a) 22.5 x 10^1

Step-by-step explanation:

9 x 10^3 / 4 x 10^2 = 22.5

2.25 x 10^1 = 22.5

amm18122 years ago
4 0

Answer:

The African Elephant is 2.27 times heavier than a African Lion.

Step-by-step explanation:

9 × 103 pounds = 927E.

4 × 102 pounds = 408L.

You might be interested in
Please help me with this
lions [1.4K]
B, c, e . Hope this helped!
7 0
3 years ago
How do you solve this?
iragen [17]

                  - - - - - - - - - - - - - - - - - - - - - - - - - - -

\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

How do you solve this? [question in attachment]

\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}

In order to find the perimeter of a shape, we should add all of its sides.

Since a triangle has only 3 sides, we add 3 sides together, like so:-

      ⇒ 9x-7+12x-13+3x+8

Combine like terms:-

    ➪ 9x+12x+3x-7-13-8

Which simplifies to

     ➪9x+15x-7-21

On further simplification,

➪24x-28

So we conclude that the perimeter of the triangle is 24x-28 units.

<h3 /><h3>Good luck.</h3>

              - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

7 0
2 years ago
What is the missing reason in the proof
exis [7]

Answer:

corresponding angles

5 0
3 years ago
There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

We have given that:

There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp. Each year, 10 new crocodiles join the swamp

Part A:

According to the above mentioned statement the function for representing the number of alligators and crocodiles in the swap throughout the year is:

Alligators = y=20(1.25)^x (x represents years)

crocodiles: y=10x+25

Part B:

Number of alligators after 4 years in the swap = y=20(1.25)^x

Number of alligators after 4 years in the swap = y=20(1.25)^4

Number of alligators after 4 years in the swap=48.82

This shows that about 48 to 49 alligators will be there in the swap after 4 year

Number of crocodiles after 4 years in the swap = y= 10(4)+25 = 65

Part C:

We will use the graph method to solve this part:

After approximately 7 years, the number of animals of each type will be the same, 95.

7 0
3 years ago
If four bells toll at intervals of 8,9,12 and 15 minutes respectively. If they toll at 3 pm when will they toll together
miv72 [106K]
Ur basically looking for the common multiple of the numbers 8,9,12,and 15.
LCM of these numbers is 360. 

so 360 minutes = (360/60) = 6 hrs

and 6 hrs from 3 p.m. would be : 9 p.m. <== ur answer
7 0
2 years ago
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