Question

Help with this question, ASAP!!

Answer 1

Answer:

Option D). 171 feet is correct

Step-by-step explanation:

Given that a toy rocket is launched from 42 feet above the ground.

The height is rocket is given by f(t)=$-16t^{2} +91t+42$

To find the height of the rocket above the ground after 3seconds :

Given that f(0)=42

Take t=3

f(t)=$-16t^{2} +91t+42$

f(3)=$-16(3)^{2} +91(3)+42$

f(3)=$-16(9) +91(3)+42$

f(3)=$-144 +273+42$

f(3)=171 feet

Therefore, option D). 171 feet is correct