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Alex17521 [72]
3 years ago
15

Does the scatterplot below relate to a statistical question? Explain

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0

Answer: Yes we have a statistical question

This is because we have a sample of data, and it's useful and meaningful to compute sample statistics on that data. For example, we can form a regression line to help see the pattern that the older you get, the more you tend to study. There isn't a direct connection and there are confounding variables, but there's a positive correlation of some sort.

Once we figure out the sample statistics, we can use it to estimate the population at large. The population could be students at a certain school or certain area of the country; while these dots represent the small sample from that population. Keep in mind that anyone in the sample must be part of the population, but not vice versa. We say that the sample is a subset of the population.

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Tanh(2a)==1/2 then a=?​
stepladder [879]

Answer:

2a=1/2

a=1/4

Step-by-step explanation:

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I dont really understand this prob explain or show a picture
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Find the sum of the first 9 terms in the following geometric series.
iogann1982 [59]

Answer:

127.75

Step-by-step explanation:

64+32+16+8+4+2+1+.5+.25=127.75

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3 years ago
1,305 divided by 31,828 x100
matrenka [14]

Answer:

4 \frac{1}{10}

Step-by-step explanation:

=> \frac{1305}{31828} * 100

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3 years ago
A Web ad can be designed from four different colors, three font types, five font sizes, three images, and five text phrases. A s
Varvara68 [4.7K]

Answer:

P(A∪B)=17/20 or 0.85

P(A∪B')=2/5 or 0.4

P(A'∪B')=4/5 or 0.8

Step-by-step explanation:

There are four font colors so each color had equal chance and thus,

P(A)=1/4

There are 5 font sizes and so not the smallest fonts are 4.Thus,

P(B)=4/5

P(A∪B)=P(A)+P(B)-P(A∩B)

The design is generated randomly so event A and event B are independent.

P(A∩B)=P(A)*P(B)

P(A∩B)=1/4(4/5)=1/5

P(A∪B)=P(A)+P(B)-P(A∩B)

P(A∪B)=1/4+4/5-1/5=1/4+3/5

P(A∪B)=17/20 or 0.85

P(A∪B')=P(A)+P(B')-P(A∩B')

P(B')=1-P(B)=1-4/5=1/5

P(A∩B')=P(A)*P(B')=1/4*1/5=1/20

P(A∪B')=P(A)+P(B')-P(A∩B')

P(A∪B')=1/4+1/5-1/20=9/20-1/20=8/20

P(A∪B')=2/5 or 0.4

P(A'∪B')=P(A∩B)'

P(A'∪B')=1-P(A∩B)

P(A'∪B')=1-1/5=4/5

P(A'∪B')=4/5 or 0.8

5 0
3 years ago
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