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sdas [7]
3 years ago
12

It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular

train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?
(A) z(y – x)/x + y
(B) z(x – y)/x + y
(C) z(x + y)/y – x
(D) xy(x – y)/x + y
(E) xy(y – x)/x + y
Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

B

Step-by-step explanation:

To solve this, we use ratio.

Firstly, we need to know the number of hours traveled. The total number of hours traveled = x+y

Ratio of this used by high speed train = x/(x +y).

Total distance traveled before they meet = [x/(x + y)] × z

For low speed train = [y/(x + y)] × z.

The difference would be distance by high speed train - distance by low speed train.

= z [ (x - y)/x + y)]

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(csc x - 1) (csc x + 1)
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<h2>Explanation:</h2>

Here we have the following expression:

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So we need to extend this. Remember that the difference of squares tells us:

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4 0
3 years ago
Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,
Dmitry_Shevchenko [17]

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

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now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

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T = 1250

this is the total amount of waste

6 0
2 years ago
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