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Romashka-Z-Leto [24]
3 years ago
7

A second-order linear differential equation for y(t) is said to be homogeneous if... every term involve either y or its derivati

ves, every term involve either tor its derivatives. every term is nonconstant. all terms are either constants or continuous functions in t.
Mathematics
1 answer:
swat323 years ago
4 0

Answer: Hello!

A second order differential equation has the next shape:

y''(t) + p(t)y'(t) + q(t)y(t) = g(t)

where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.

And is called homogeneus when g(t) = 0, so you have:

y''(t) + p(t)y'(t) + q(t)y(t) = 0

Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.

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deff fn [24]

2. c = 47,000 × n, where c is the cost of n number of bears.

3. a) The cost to ride 5 rides = $20.50, the cost to ride 8 rides = $28.00

The equation for the pattern, C(x) = 15.50 + 2.50 (r - 3), where C is the cost and r is the number of rides.

b) The cost to ride 12 rides = $36.00.

Step-by-step explanation:

Step 1; To find the cost of one bear, we divide the cost of bears by the number.

If 4 bears cost $188,000, 1 bear costs = \frac{188000}{4} = $47,000.

If 7 bears cost $329,000, 1 bear costs = \frac{329,000}{7} = $47,000.

So the equation is c = 47,000 × n, where c is the cost to buy n bears.

Step 2; For every additional ride, the price increases by $2.50. So the equation for the pattern is C(x) = 13.50 + 2.50 (x - 3).

When the number of rides is 5, C(5) = 15.50 + 2.50 (5-3) = 15.50 + 2.50 (2) = 15.50 + 5.0 = $20.50.

When the number of rides is 8, C(8) = 15.50 + 2.50 (8-3) = 15.50 + 2.50 (5) = 15.50 + 12.50 = $28.00.

When the number of rides is 12, C(12) = 15.50 + 2.50 (12-3) = 15.50 + 2.50 (9) = 13.50 + 22.5 = $36.00.

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