Ask question

Ask question

All categories

3 years ago

11

Carl is loud and obnoxious. According to your lesson, what kind of difficult person is Carl?

2 answers:

Rainbow [258]3 years ago

6 0

Can you please link the lesson?

andreev551 [17]3 years ago

5 0

Carl is difficult point out

You might be interested in

All of the following are good questions to ask yourself when determining your strengths and skills except:

Llana [10]

What skills do i need to improve Apex

6 0

3 years ago

Read 2 more answers

If 50. 0 g of ch₃oh (mm = 32. 04 g/mol) are added to a 500. 0 ml volumetric flask, and water is added to fill the flask, what is

Elza [17]

Taking into account the definition of molarity, the concentration of CH₃OH in the solution is 3.12 $\frac{moles}{liters}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liters}$ .

<h3>Concentration of CH₃OH</h3>

In this case, you know:

number of moles= 50 g× $\frac{1 mole}{32.04 g}$ = 1.56 moles, being 32.04 $\frac{g}{mole}$ the molar mass of CH₃OH
volume= 500 mL= 0.5 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{1.56 moles}{0.500 L}$

Solving:

<u><em>Molarity= 3.12 </em></u> $\frac{moles}{liters}$

Finally, the concentration of CH₃OH in the solution is 3.12 $\frac{moles}{liters}$ .

Learn more about molarity:

<u>brainly.com/question/9324116</u>

<u>brainly.com/question/10608366</u>

<u>brainly.com/question/7429224</u>

8 0

2 years ago

Calculate the mass of hydrogen in 57. 010 grams of ammonium hydrogen phosphate.

erastovalidia [21]

The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g

<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>

1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g

<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>

Mass of H = 6H = 6 × 1 = 6 g

<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>

115 g of (NH₄)H₂PO₄ contains 6 g of H.

Therefore,

57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H

Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄

Learn more about mass composition:

brainly.com/question/13531044

4 0

3 years ago

What do performers consider when playing a piece of music?

guajiro [1.7K]

Answer:

style and commitment

Explanation:

for those who want to do music for performance would have to follow these 2 things to have a great career

4 0

3 years ago

Read 2 more answers

Which topic is suitable for the size and scope of a five-paragraph essay? the history of weather science and climatology the stu

dsp73

Answer:

D is the correct answer

Explanation:

Edge 2021

7 0

3 years ago