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inn [45]
3 years ago
5

Plz help me!?

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

g 6vz -5.0,0

Step-by-step explanation:

It is because hgg

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Divide 4200 by a multiple of 10 so that the quotient is also a multiple of 10
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Answer: Well if you divide 4200 by 42, you will get 100, which is a multiple of 10

Step-by-step explanation:

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Can someone help me with the 2 highlighted questions?
dexar [7]

Answer:

2. domain: {3,4,5,6,7}; range: {2,3,4,5,6}

4. IS a function

Step-by-step explanation:

2. The <em>domain</em> is the list of first numbers of each pair.

The <em>range</em> is the list of second numbers.

4. If each value on the left only has <em>one arrow</em> coming from it, the relation <u>is</u> a function. That is the case here.

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Contrast that to the problem above (3.). In that one, the number 4 1/2 has two arrows coming from it. That relation is NOT a function.

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3 years ago
Suppose you roll a die 5 times. What is the probability of getting at least one odd number ​?
Simora [160]

Answer: 1/2 or 50%

Step-by-step explanation:        

A dice has 6 numbers; 1,2,3,4,5,6

3 of which are odd numbers

which means:

p(event)= number of favorable outcomes/ number of possible outcomes

p(odd)=3/6

3/6=1/2 or 50%

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2 years ago
In a test of a particular weight loss program, weights of 40 subjects are recorded before and after the program. The before-and-
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I just took the quiz, the answer is A: Critical values=0.312; there is sufficient evidence to support a claim of a linear correlation between before-and-after weights.

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3 years ago
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Short Response
garik1379 [7]

Answer:

(a)2(89x+84)

(b)2(89x+84-x^2\pi)

Step-by-step explanation:

The dimensions of the larger rectangular field are:

  • Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

  • Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain =\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi

Area of the Field that does not include the soccer  field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)

8 0
4 years ago
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