A..
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The formula for the number of bacteria at time t is 1000 x (2^t).
The number of bacteria after one hour is 2828
The number of minutes for there to be 50,000 bacteria is 324 minutes.
<h3>What is the number of bacteria after 1 hour?
</h3>
The exponential function that can be used to determine the number of bacteria with the passage of time is:
initial population x (rate of increase)^t
1000 x (2^t).
Population after 1 hour : 1000 x 2^(60/40) = 2828
Time when there would be 50,000 bacteria : In(FV / PV) / r
Where:
- FV = future bacteria population = 50,000
- PV = present bacteria population = 1000
- r = rate of increase = 100%
In (50,000 / 1000)
In 50 / 1 = 3.91 hours x 60 = 324 minutes
To learn more about exponential functions, please check: brainly.com/question/26331578
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<span>RS= 8y + 4, ST = 4y + 8, and RT = 36
RS + ST = RT
</span>8y + 4 + 4y + 8 = 36
12y + 12 = 36
12y = 24
y = 2
answer
y = 2 (first choice)
-6 + 7 = 1 and -6*7 = -42
So f(x) = (x + 7)(x - 6)
Answer:
a) P(E|F) = 0.5
b) P(F|E) = 0.167
c) P(E|F') = 0.625
d) P(E′|F′) = 0.375
Step-by-step explanation:
P(E) = 0.6
P(F) = 0.2
P(E n F) = 0.1
a) P(E|F) = Probability of E occurring, given F has already occurred. It is given mathematically as
P(E|F) = [P(E n F)]/P(F) = 0.1/0.2 = 0.5
b) P(F|E) = Probability of F occurring, given E has already occurred. It is given mathematically as
P(F|E) = [P(E n F)]/P(E) = 0.1/0.6 = 0.167
c) P(E|F′) = Probability of E occurring, given F did not occur. It is given mathematically as
P(E|F') = [P(E n F')]/P(F')
But P(F') = 1 - P(F) = 1 - 0.2 = 0.8
P(E n F') = P(E) - P(E n F) = 0.6 - 0.1 = 0.5
P(E|F') = 0.5/0.8 = 0.625
d) P(E′|F′) = [P(E' n F')]/P(F')
P(F') = 0.8, P(Universal set) = P(U) = 1
P(E' n F') = P(U) - [P(E n F') + P(E' n F) + P(E n F) = 1 - (0.5 + 0.1 + 0.1) = 0.3
P(E′|F′) = 0.3/0.8 = 0.375