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3 years ago

9

At a wedding, there are 456 people spread out amongst 45 tables. There are no empty seats. The reception hall has tables that si

t 12 people or 8 people. Write a system of equations that can be used to find the number of each type of table the restaurant has.

1 answer:

uysha [10]3 years ago

3 0

Thats a lot of people for one resturant

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Harry charges $4 to babysit for the first hour. For each additional hour, he charges

IRISSAK [1]

Harry would earn total money equal to $32.50 babysitting.

Since Harry charges 50% more for each additional hour as he did for the previous hour, then

he charges 1.5 or 3/2 times as much as he did for the previous hour.

<h3>What is the charge?</h3>

Term Definition Money charge refers to a special expense entry and allows an administrator to track changes in a project's billing.

Harry charges $4 for the first hour.

Harry then charges

3/2 × $4 = $6 for the second hour.

Harry then charges 3

3/2 × $6 = $9 for the third hour.

Harry then charges 3

3/2 × $9 = $ 27/2 = $13.50 for the fourth hour.

Therefore, for 4 hours of babysitting

Harry would earn $4 + $6 + $9 + $13.50 = $32.50.

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2 years ago

Si a cero se le resta cualquier número entero el resultado siempre es el

mina [271]

Please comment this in english.

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3 years ago

Taj had 15 books. He gave some of the books to his friends.

deff fn [24]

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3 years ago

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Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti

sukhopar [10]

The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

At Morning, the probability that Marvin does not teleport = 2/3

Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = $\frac{2}{3}*\frac{2}{3}=\frac{4}{9}$

Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.

Probability that Marvin teleports atleast once during the day = $1-\frac{4}{9}=\frac{5}{9}$

5 0

3 years ago

Can someone plsss help :)

OLga [1]

Set equal to eachother
(2x+1) = 79
Subtract 1 from both sides
2x=78
Divide 2 from both sides
2x/2=78/2
X= 39

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4 years ago