The probability that only one shows a 2.
There are 36 different outputs (6x6) = 36
There are 6 combinations where the first cube shows a 2, these are 2,1;2,2;2,3;2,4;2,5; and 2.6
There are 6 combinations where the second cube shows a 2: 1,2;2,2;3,2;4,2;5,2; and 6,2.
Of those one combination on each set shows two 2.
Then the number of combinations with only one 2 are 6 - 1 + 6 -1 = 10
Now the probabilit is 10 out of 36 = 10 / 36 = 5 / 18
False It can't be parallel It's gonna be intersecting or perpendicular
Answer:
Step-by-step explanation:
you need to simplify 8/20
8/20 can be put into the greatest common factor which is 4
then divide both sides by 4 this equals to 2/5
So yes they are
For this question, we can divide both numbers by 8, as they are both divisible by 8. Then, we will be left with our answer, which will be a 3 degree drop every hour.
