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PSYCHO15rus [73]
3 years ago
12

Prove that n^2 > 2n + 1 for all natural numbers n >= 3

Mathematics
1 answer:
mafiozo [28]3 years ago
7 0

{n}^{2}  - 2n - 1 > 0
n = 3 >  > 9 - 6 - 1 = 2 > 0
suppose the following is true
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The complete question in the attached figure

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