Answer:
x^2+(y-1)^2=25
Step-by-step explanation:
eqn of circle : (x-h)^2+(y-k)^2=r^2
center of circle = (h,k)
hence, the center of the current circle is (2,3)
moving 2 units to the left would make the center (0,1)
the radius would remain the same (5) , hence the new eqn would be
(x-0)^2+(y-1)^2=25
x^2+(y-1)^2=25
If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,

The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
Answer:
28
Step-by-step explanation:
The other two angles that are adjacent to the right angle in a right triangle add up to 90. So




Answer:
Step-by-step explanation:
im not sure if it is right,but here is my thought since its gonna be half first you do the 4x2x2=16 divide 16 by 2 witch will give you have of 16 witch will also give you 8
Answer:
first option
Step-by-step explanation:
Given
| x + 4 | = 2
The absolute value function always produces a positive value but the expression inside can be positive or negative, thus
x + 4 = 2 ( subtract 4 from both sides )
x = - 2
OR
- (x + 4) = 2, distribute left side
- x - 4 = 2 ( add 4 to both sides )
- x = 6 ( multiply both sides by - 1 )
x = - 6
Thus solutions are x = - 2, x = - 6
These are represented on the graph by solid blue circles at x = - 2, x = - 6
The first option represents the solution