Answer:We start each project to get some business benefits. We design it to achieve users and other stakeholder’s satisfaction. And we build it to improve organization KPIs. But, we live in a world where the project faces many uncertainties. These uncertainties or risks can prevent from achieving our project goals or objectives. So, it is critical that we identify them in time to take care of their effective responses.
The more we know our risks, the more we can evaluate and prioritize them timely for:
Reducing their probable negative impacts, or
Increase their likely positive impacts
We can use Qualitative Risk Analysis and Quantitative Risk Analysis techniques to evaluate and prioritize risks. I see there are a lot of confusions around how these two techniques are different from each other. In this blog, I will address these confusions and differences between these two techniques.
Before we get into the difference between qualitative and quantitative risk analysis/assessment, it is mandatory to understand how we perform risk analysis in projects. Below is the summarized demonstration of the risk analysis:
Explanation:
Answer:
The complete program is as follows:
def convert_distance(miles):
km = miles * 1.6 # approximately 1.6 km in 1 mile
return km
my_trip_miles = 55
# 2) Convert my_trip_miles to kilometers by calling the function above
my_trip_km =convert_distance(my_trip_miles) #3) Fill in the blank to print the result of the conversion
# 4) Calculate the round-trip in kilometers by doubling the result,
print("The distance in kilometers is " +str(my_trip_km))
# and fill in the blank to print the result
print("The round-trip in kilometers is " + str(my_trip_km * 2))
Explanation:
<em>The program is self-explanatory because I used the same comments in the original question.</em>
Answer:
It can translate text to voice
Explanation:
Answer:
#include<iostream>
using namespace std;
int main (){
int n1, n2;
cout<<"Enter 1st number";
cin>>n1;
cout<<"Enter 2nd number";
cin>>n2;
if(n1<n2){
cout<<"The 1st number is the smallest"<<endl<<" is= "<<n1;
}
else{
cout<<"The 2nd number is the smallest"<<endl<<" is= "<<n2;
}
}
return 0;
