Answer:
Keq = [H₂]⁴[CSe₂]/[CH₄][H₂Se]².
Explanation:
- The equilibrium constant expression is the ratio of the concentrations of the products over the reactants.
<em>CH₄(g) + 2H₂Se(g) ⇄ 4H₂(g) + CSe₂(g).</em>
<em></em>
<em>∴ Keq = [products]/[reactants] = [H₂]⁴[CSe₂]/[CH₄][H₂Se]².</em>
Remember that a conjugate acid-base pair will differ only by one proton.
None of the options you listed are conjugate acid-base pairs as none of them differ only by one proton (or H⁺)
An example of a conjugate acid-base pair would be NH₃ and NH₄⁺NH₃ + H₂O --> NH₄⁺ + OH⁻NH3 is the base, and NH₄⁺ is the conjugate acid
the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Explanation:
Litmus paper is your answer
please mark as brilliant
