Question

How many times a one pound (2.2 kg) block of iron can be split in half before it stops being iron.

Answer 1

Answer:

Number of  times a one pound (2.2 kg) block of iron can be split in half before it stops being iron

= 84.29 times

Explanation:

Atoms : It is the smallest indivisible particle of the matter .

The atom can not be further breakdown .

Here in this question , we have to find the number of atoms (because it is the last possible situation for breaking of atom)

Mole : The quantity of the substance that contain as many particles as present in 12 g of C-12.It is quantity which Avogadro number(N0) of particles

$N_{0}=6.022\times 10^{23}$

1.First calculate the number of moles of Fe in 2.2Kg Block

Mass of  Iron (Fe) = 55.845 amu

Molar mass of Iron = 55.845 g

Given mass = 2.2 kg

1 kg = 1000 g

2.2 kg = 2200 g

$moles = \frac{given\ mass}{Molar\ mass}$

$moles = \frac{2200}{55.845}Moles of Fe = 39.39 2.Calculate the number of particles of Fe in 39.39 moles of Block[tex]moles = \frac{Number\ of\ Particles}{Avogadro\ number}$

$Avogadro\ number = 6.022\times 10^{23}$

moles = 39.39

$39.39 = \frac{Number\ of\ Particles}{N_{0}}$

$Number\ of\ Particles=39.39\times 6.022\times 10^{23}$

$Number\ of\ Particles= 2.37\times 10^{25}$

$2.37\times 10^{25}$ atoms

3.Calculate Number of time(n), the block is split into -Half

$2^{n}=2.37\times 10^{25}$

Take log both side ,

$n\ log2 = log(2.37\times 10^{25})$

Solve for n, you get

n= 84.29 (convert it to nearest whole number)

n = 84 times