All categories

3 years ago

What is the balance as a result of having a credit of $84 and a debit of $29?

1 answer:

34kurt3 years ago

8 0

Hello!
I would be more than happy to help!
So to find the balance use this equation.

Balance = Credit- Debit

In other words, to find BALANCE... You Subtract Debit from Credit

whats my credit? 84$
Whats my debit? 29$
Whats my balance? Lets find out! How? Well, lets subtract my credit (84) from my debit (29).

84-29= 55

Balance =55

Hope this helped!

You might be interested in

10 points if you solve this one problem.

zalisa [80]

Answer:

150

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

<1 + <2 = <3

3x+11 + 3x+19 = 7x+10

Combine like terms

6x+30 = 7x+10

Subtract 6x from each side

6x -6x+30 = 7x-6x+10

30 = x+10

Subtract 10 from each side

30-10 = x+10-10

20 =x

We need to find angle 3

<3 = 7x+10

= 7(20)+10

= 140+10

= 150

7 0

2 years ago

Find the difference between 7 1/2 and 2 3/4

NNADVOKAT [17]

Answer:

4 $\frac{3}{4}$ or 4.75

Step-by-step explanation:

first we're going to convert the number into improper fractions.

7 $\frac{1}{2}$ = $\frac{15}{2}$ and 2 $\frac{3}{4}$ = $\frac{11}{4}$

For subtracting it is suitable to adjust both fractions to an equal denominator, so we're going to multiply $\frac{15}{2}$ x2, it'll equal the same number.

So now we have $\frac{30}{4}$ - $\frac{11}{4}$ , 30-11= 19.

$\frac{19}4}$ simplified is, 4 $\frac{3}{4}$ .

As you can see I also added 4.75 as an answer, that's if the answer must be a decimal.

I hope this helps you!

3 0

2 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$