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inna [77]
3 years ago
13

What is the balance as a result of having a credit of $84 and a debit of $29?

Mathematics
1 answer:
34kurt3 years ago
8 0
Hello!
 I would be more than happy to help!
So to find the balance use this equation.

Balance = Credit- Debit


 In other words, to find BALANCE... You Subtract Debit from Credit
 
whats my credit? 84$
Whats my debit? 29$
Whats my balance? Lets find out! How? Well, lets subtract my credit (84) from my debit (29).

84-29= 55

Balance =55
 

Hope this helped!

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HELLPPPPP PLS INCLUDE EXPLANATION ON HOW TO DO IT SO I CAN DO IT ON MY OWN!!!!
ale4655 [162]

Answer: 0.000021 in scientific notation is

2.1 × 10-5

Step-by-step explanation:

All numbers in scientific notation or standard form are written in the form

m × 10n, where m is a number between 1 and 10 ( 1 ≤ |m| < 10 ) and the exponent n is a positive or negative integer.

To convert 0.000021 into scientific notation, follow these steps:

Move the decimal 5 times to right in the number so that the resulting number, m = 2.1, is greater than or equal to 1 but less than 10

Since we moved the decimal to the right the exponent n is negative

n = -5

Write in the scientific notation form m × 10n

= 2.1 × 10-5

Therefore,

2.1 × 10-5 is the scientific notation form of 0.000021 number and 2.1e-5 is the scientific e-notation form for 0.000021

** Hope this helps you! Good Luck!

3 0
3 years ago
A jeweler who buys a ring from a jewelry maker for $125 marked with the price by 135% for sale in the store what is the selling
siniylev [52]
Marked up by 135% means
new price=original price+(original price times markup) =125+(125 times 1.35)=293.75
tax
293.75 times 0.075=22.03125

293.75-22.03125=271.718 so aprox $271.72


selling price would be $271.72
6 0
3 years ago
Read 2 more answers
Kate and Margaret spend $42.60 on dinner at a restaurant
dlinn [17]

H, it's asking for the total amount of money spent. so you add.

3 0
2 years ago
Opposite reciprocal of -2/3? geometry/algebra
Ulleksa [173]
The answer would be -3/2

A reciprocal is the inverse of a number.
When using this in fractions just switch the numerator and denominator. This is done by dividing the fraction by one, but in the case of a negative fraction you would divide by negative 1.
8 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}&#10;\textit{circumference of a circle}\\\\ &#10;2\pi r&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{arc's length}\\\\&#10;s=\cfrac{\theta r\pi }{180}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+&#10;\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}&#10;\\\\\\&#10;15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}&#10;\textit{area of a circle}\\\\ &#10;\pi r^2&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{area of a sector of a circle}\\\\&#10;s=\cfrac{\theta r^2\pi }{360}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}&#10;\\\\\\&#10;90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
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