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Anarel [89]
4 years ago
6

PLz help will mark as brainlest

Mathematics
1 answer:
aliina [53]4 years ago
8 0

Answer:

B

Step-by-step explanation:

Not counting human error he should get exactly eight questions right using scicence, but since it is random there is margin of error that may disfigure the outcome.

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joyce has between 25 to 75 coloured beads. when she makes them into groups of 9, 8 beads are left out. when she groups into grou
hoa [83]

Answer:

Joyce has total 62 colored beads.

Step-by-step explanation:

For making groups of 9, let the number of beads be x.

total beads = 9x + 8

For making groups of 8, let the number of beads be y.

total beads = 8y + 6

As the total number of beads in both cases are same so,

   9x + 8= 8y + 6

or, 9x-8y = -2

Now lets check the values through hit and trial;

First check; x=6, y=7

   9*6 - 8*7 = -2

or, 54- 56 = -2

or, -2 =-2

This satisfies our equation.

Hence; Total beads = 9*6 + 8 = 62

The total number of beads joyce had is 62.

7 0
3 years ago
Read 2 more answers
Use a definition, postulate, or theorem to find the value of x in the figure described.
Yuri [45]
The Definition of Linear Pair states that both ∠ABC and ∠CBD are equal to 180 degrees. In the question, this tells you that 
m∠ABC and m∠CBD = (3x − 6). 
So, you're equation should be (3x - 6) + (3x - 6) = 180. 
You would then solve to get 6x - 12 = 180, 6x = 192, x = 32
x=32, and we used the Linear Pair Theorem (C)

5 0
3 years ago
Please help ME PLEASEEE
saw5 [17]

Answer:

3x² + 2x + 3 / b

Step-by-step explanation:

This is the correct answer. Hope this helps

5 0
2 years ago
Which expression is a rational number? A) ( 25 + 25 )2 B) ( 25 + 50 )2 C) ( 50 + 75 )2 D) ( 25 + 72 )2
tigry1 [53]
I believe it's a hope it helps
6 0
3 years ago
What are the solutions to the quadratic equation x^2-16=0
maks197457 [2]
Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

\mathsf{x^2 - 16 = 0}

Add 16 to both sides:

\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}

Take the square root:

\mathsf{\sqrt {x^2} = \pm\sqrt{16}}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}

Therefore:

\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}
4 0
4 years ago
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