All categories

3 years ago

If g(x)=(1/4)^x, find g(-3)

Mathematics

1 answer:

swat323 years ago

4 0

G(x) = (1/4)^x

Find g(-3) this means to replace x with -3

G(-3) = (1/4)^-3

Apply the negative exponent rule :

A^-b = 1/a^b

G(-3) = 1/(1/4)^3

G(-3) = 1/ (1/64)

G(-3) = 64

Answer: 64

You might be interested in

Question 2 (2 points)

hoa [83]

Answer:

4) The limit does not exist.

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}$

Step 2: Find Left-Side Limit

Substitute in function [Left-Side Limit]: $\displaystyle \lim_{x \to 5^-} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0$

Step 2: Find Left-Side Limit

Substitute in function [Right-Side Limit]: $\displaystyle \lim_{x \to 5^+} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ since $\displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)$ , $\displaystyle \lim_{x \to 5} f(x) = \text{DNE}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

3 years ago

- 5(x + 9) =- 3(x – 8) – 2x help

djyliett [7]

Do you need to show work?

5 0

3 years ago

Please answer all for brainlest and thanks !!! I'm begging :((

Eva8 [605]

You can find a unit rate when given a rate by dividing the the second number in the rate (if you had 3:4, you would divide 4) by the same number. (in the problem I gave you, you would divide 4 by 4 to get 1 then divide 3 by 4.) Then you would have the unit rate. Sorry if that didn't make any sense.

4 0

3 years ago

Read 2 more answers

Prove that the diagonals of a parallelogram bisect each other. The midpoints are the same point, so the diagonals _____

Molodets [167]

Answer:

Below

Step-by-step explanation:

To prove that the diagonals bisect each other we should prove that they have a common point.

From the graph we notice that this point is E.

ABCD is a paralellogram, so E is the midpoint of both diagonals.

●●●●●●●●●●●●●●●●●●●●●●●●

Let's start with AC.

● A(0,0)

● C(2a+2b,2c)

● E( (2a+2b+0)/2 , (2c+0)/2)

● E ( a+b, c)

●●●●●●●●●●●●●●●●●●●●●●●●

BD:

● B(2b,2c)

● D(2a,0)

● E ( (2a+2b)/2 , 2c/2)

● E ( a+b ,c)

●●●●●●●●●●●●●●●●●●●●●●●●●

So we conclude that the diagonals bisect each others in E.

8 0

3 years ago

Describe how to transform the quantity of the fifth root of x to the seventh power, to the third power into an expression with a

Pie

Answer:

unnun

Step-by-step explanation:

3 0

2 years ago