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dimaraw [331]
3 years ago
14

V and 303 more equals 21

Mathematics
1 answer:
juin [17]3 years ago
5 0
Answer: V= -282

Explanation: if you subtract 21 from 303 you end up with -282 and to recheck you can add -282 with 303 and the total would be 21.
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How could you find an even better estimate of the square root of 2
vodomira [7]

Answer:

First of all you need to know the \sqrt {4} it's equal to 2 and

\sqrt {1} which is the number is between 1 and 2 and between that number there maybe the possibilities of above 0.5 or under 0.5

After that Figure out which one was bigger?  \sqrt {2} or \sqrt {3} ? The answer is \sqrt {3} and \sqrt {3} also near to \sqrt {4} so it should be above 0.5 .

So we know that \sqrt {2} is between 1 and 1.5.

Hopes that information was help you a lot

6 0
3 years ago
PLZ HELP!!! Use limits to evaluate the integral.
Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

r_i=\dfrac{2i}n

where 1\le i\le n. Each interval has length \Delta x_i=\frac{2-0}n=\frac2n.

At these sampling points, the function takes on values of

f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}

We approximate the integral with the Riemann sum:

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3

Recall that

\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4

so that the sum reduces to

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}

Just to check:

\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28

4 0
3 years ago
GEOMETRY PLZZZZZ HELPPPPP
USPshnik [31]

Answer:

(x,y) becomes (-y,x) so (3,2) would become (-2,3)

3 0
2 years ago
A map has a scale of 1 cm to 16 km.
ra1l [238]
1cm = 16km

1cm • x = 23.1cm
x = 23.1

16km • 23.1 = 369.6km

The real distance is 369.6km.
4 0
3 years ago
Here is the histogram of a data distribution. All class widths are 1.
stich3 [128]

The median of the data is 5 if the all class widths are 1, option (C) is correct.

<h3>What is the median?</h3>

A median is a middle number in a series of numbers that have been arranged to lift, and it might be more informative of the set of data than the average. When there are extremes in the sequences that might affect the average of the numbers, the median is sometimes employed instead of the mean.

In the histogram, 15 data values are given:

1, 2, 2, 3, 3, 3, 4, 5, 6, 6, 7, 7, 7, 8, 9

The mid-value is 5 which is on the 8th place

Thus, the median of the data is 5 if the all class widths are 1, option (C) is correct.

Learn more about the median here:

brainly.com/question/21396105

#SPJ1

8 0
2 years ago
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