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tatiyna
3 years ago
10

Katie says the graph of y=8 . (1/2)^x is the same as the graph of f(x)=8 . (1/2)^x. Do you agree? Explain your reasoning.

Mathematics
2 answers:
dangina [55]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

Katie's Graph equation: y=8(\frac{1}{2})^x

Another graph equation: f(x)=8(\frac{1}{2})^x

Since the right hand side of both the equations of graphs are equal

So, Left hand side of both equations of graphs must be equal

So, : y=f(x)

So, the graph of y=8(\frac{1}{2})^x  is the same as the graph of   f(x)=8(\frac{1}{2})^x

Refer the attached figure

Purple line : f(x)=8(\frac{1}{2})^x

Red line :  y=8(\frac{1}{2})^x

Gelneren [198K]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Yes, the graph of y=8{\times}(\frac{1}{2})^{x} is same as the graph of f(x)=8{\times}(\frac{1}{2})^{x} because the right hand side of both the equations is equal that is 8{\times}(\frac{1}{2})^{x}, therefore by substituting different values of x in both equations, we obtain the same graph.

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Part B)

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Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
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Where <em>A</em> is the final amount, <em>P</em> is the initial amount, <em>r</em> is the interest rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the number of years.

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Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

\displaystyle A = Pe^{rt}

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<em />\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}

In conclusion, about $3692.47 should be deposited.

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