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3 years ago

What is 3a+2b-5a+b simplified?

Mathematics

2 answers:

marishachu [46]3 years ago

7 0

Answer:

-a + b

Step-by-step explanation:

REY [17]3 years ago

3 0

Answer:

-2a + 3b

Step-by-step explanation:

Since you need to simplify the expression, you need to combine like terms. 3a and -5a are like terms because they both have the variable a. 3a + -5a equals -2a. 2b + b equals 3b. Since b would equal 1. If you combine them together, you get -2a + 3b.

Hope this helps!!

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A=3.14r^2 and d=12 A=?

zvonat [6]

$\huge\boxed{113.04}$

Diameter ( $d$ ) is equal to twice the radius ( $r$ ). So, find the radius by dividing $\frac{12}{2}$ . The radius, or $r$ , is $6$ .

Substitute in the value. $A=3.14*6^2$

Follow the order of operations and solve the exponent first. $A=3.14*36$

Multiply. $A=\boxed{113.04}$

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3 years ago

Felix has $50 in a savings account that earns 5% interest, compounded annually. To the nearest cent, how much interest will he e

qwelly [4]

Answer:

$55.13

Step-by-step explanation:

50 * 1.05 = 52.5

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52.5 * 1.05 = 55.125

This rounds up to 55.13, your final answer!

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3 years ago

How do you do long division how do you do long division on 35 / 2

deff fn [24]

17
2 35
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3 years ago

Read 2 more answers

Find the 137th odd number.

KIM [24]

The first odd number is 1. The next is 2 more than the previous one.

It's an arithmetic sequence.

The general term of an arithmetic sequence:

$a_n=a_1+(n-1)d$

a_n - n-th term

a_1 - first term

d - common difference.

We have

$a_1=1,\ d=2,\ n=137$

Substitute:

$a_{137}=1+(137-1)(2)=1+(136)(2)=1+272=273$

<h3>Answer: 137th odd number is equal 273.</h3>

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3 years ago

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Help please! | 2x^2 + 5x + 3 | > 0 solve the inequality

vovikov84 [41]

Factorize the quadratic.

$2x^2 + 5x + 3 = (2x + 3) (x + 1)$

We have $|ab| = |a||b|$ , so

$|2x^2 + 5x + 3| = |2x + 3| |x + 1| > 0$

Now, both $|2x+3|\ge0$ and $|x+1|\ge0$ (since the absolute value of any number cannot be negative), so we just need to worry about when the left side is exactly zero. This happens for

$(2x + 3) (x + 1) = 0 \implies 2x+3 = 0\text{ or }x+1 = 0 \\\\ \implies x = -\dfrac32 \text{ or } x = -1$

So the solution to the inequality is the set

$\left\{x \in \Bbb R \mid x\neq-\dfrac32 \text{ and } x\neq-1\right\}$

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1 year ago