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77julia77 [94]
3 years ago
14

How is 8 the GCF of 56 and 96? Explain how to answer GCF questions.

Mathematics
1 answer:
sweet [91]3 years ago
8 0

First, you need to list the factors of all the numbers.

Factors of 56: 1, 2, 4, 7, 8, 14, 28, 56

Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

Then, find the greatest factor they have in common. In this case, it's 8.

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Can anyone can tell me that why 2 by 2 is 4
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Inez has 20 coins consisting of dimes and quarters. How many of each type does she have if all together she has $4.10
erastovalidia [21]
X = # dimes
y = # quarters

x+y = 20 so x = 20 - y
0.1x + 0.25y = 4.1

substitute x = 20 - y into 0.1x + 0.25y = 4.1

0.1x + 0.25y = 4.1
0.1(20 - y) + 0.25y = 4.1
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0.15y = 2.1
 y = 2.1 / 0.15
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answer
Dimes: 6 coins
Quarters: 14 coins

Double check
6 + 14 = 20 coins total
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6 0
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3. f(x) = – 2 x + 1
KATRIN_1 [288]

Answer:

The quadratic x2 − 5x + 6 factors as (x − 2)(x − 3). Hence the equation x2 − 5x + 6 = 0

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Similarly we can factor the cubic x3 − 6x2 + 11x − 6 as (x − 1)(x − 2)(x − 3), which enables us to show that the solutions of x3 − 6x2 + 11x − 6 = 0 are x = 1, x = 2 or x = 3. In this module we will see how to arrive at this factorisation.

Polynomials in many respects behave like whole numbers or the integers. We can add, subtract and multiply two or more polynomials together to obtain another polynomial. Just as we can divide one whole number by another, producing a quotient and remainder, we can divide one polynomial by another and obtain a quotient and remainder, which are also polynomials.

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As well as being intrinsically interesting objects, polynomials have important applications in the real world. One such application to error-correcting codes is discussed in the Appendix to this module.

8 0
3 years ago
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