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cricket20 [7]
3 years ago
8

A large cooler full of water is being drained. The relationship between the amount of water in the cooler in liters and the numb

er of minutes the cooler is draining is shown
the provided graph. What is the meaning of the intercept in this situation?
Mathematics
1 answer:
defon3 years ago
8 0

Answer:

The cooler is empty after 15 minutes.

Step-by-step explanation:

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Ill give Brainly ig just help
Vera_Pavlovna [14]

Answer:

A:  Equivelent.

B:  Not

C:   Not

D:  Equivelent.

Step-by-step explanation:

7 0
3 years ago
The lengths of a lawn mower part are approximately normally distributed with a given mean mc021-1.jpg = 4 in. and standard devia
Aleonysh [2.5K]
<span>The best answer that is given to the question that is being presented above would be 68%. Since it is normally distributed and the lengths' range fall between the first lower and upper standard deviations of the distribution (which is 68%), then the answer is 68%. </span>
5 0
3 years ago
Read 2 more answers
Y=3x+2 please graph this line
klemol [59]

Answer:

Your graph would start at the point 0,2 (over 0 up 2). Other points would be (2,8), (4,14), (-2,-4), and so on. A good website for graphing is Desmos.com .you can plug an equation in and it will graph it for you!

Step-by-step explanation:

7 0
3 years ago
Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
Can someone please help me, someone who's serious lol. PLEASE
klemol [59]

Question 11.4.10

Add up everything in the first row

13+31+24 = 68

We have 68 people with high school only education. Out of this group, 24 are conservative

So we have 24/68 = 6/17 represent the probability of selecting a conservatives person given they have high school only education.

<h3>Answer:  6/17</h3>

=======================================================

Question 11.4.15

There are 269+485 = 754 males.

Of this group, 485 are not associates.

Therefore, 485/754 = 0.64 approximately

We focus on the males only because of the phrasing "given that the recipient is male".

<h3>Answer:  0.64 </h3>

=======================================================

Question 11.4.16

Refer to the diagram below. Let's say we had 1000 people surveyed. This means we have 1000 in the bottom right corner to represent the grand total.

40% have a pet now currently and also had a pet in the past, so we have 0.40*1000 = 400 people go in the upper left corner of the table. This is the "have a pet now" row and "had a pet in the past" column.

60% do not have a pet now, so 600 people don't have a pet currently. This is the total for row 2. This must mean 1000-600 = 400 people do have a pet currently. This is the total for row 1.

The missing value in row 1 must be 0 because 400+0 = 400. Also, if a person has a pet now, they likely had it in the past as well. To be honest, the wording to set up the time scale for this problem is vague. What does it mean "in the past"? Do the researchers mean in the previous month? Year? It's not clear. Anyway, the first row consists of 400, 0 and 400 in that order.

----------------------

Then we're told that 85% have had a pet in the past. So 0.85*1000 = 850 people had a pet in the past. This goes at the bottom of the "had a pet in the past" column. This leaves 1000-850 = 150 people who didn't have a pet in the past.

Lastly, 15% of the 1000 people surveyed don't have a pet in the present and they didn't have it in the past either. Since 15% of 1000 = 0.15*1000 = 150, we will write 150 in the second entry of row 2. Notice how 0+150 = 150 for the second column. Every row should add up to the entry in the "total" column, and every column should add up to the entry in the "total" row to help check we have the correct table set up. Lastly, notice how 400+600 = 1000 and 850+150 = 1000 to further verify the table.

----------------------

By this point, the table is completely filled out. We're told "given the respondent had a pet". We only focus on the "had a pet in the past" column. 400 people have a pet now out of 850 who had a pet in the past.

Therefore, 400/850 = 0.47 approximately

<h3>Answer: 0.47</h3>

4 0
3 years ago
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