V^2 = u^2 - 2gh; where v is the final speed, u is the initial speed, g = 9.8 m/s = 0.54 ft/min is the accerelation due to gravity, h = height.
At the maximum height, the final speed is 0.
u^2 = 2gh = 2 x 0.54 x 36 = 38.58
u = sqrt(38.58) = 6.21 ft/min
Therefore, the stne should be thrown with 6.21 ft/min
Answer:
D
Step-by-step explanation:
If y = log x is the basic function, let's see the transformation rule(s):
Then,
1. y = log (x-a) is the original shifted a units to the right.
2. y = log x + b is the original shifted b units up
Hence, from the equation, we can say that this graph is:
** 2 units shifted right (with respect to original), and
** 10 units shifted up (with respect to original)
<u><em>only, left or right shift affects vertical asymptotes.</em></u>
Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.
Answer choice D is right.
Answer:
Step-by-step explanation:
The equation of the line that is parallel to the line we are trying to find is
We can recall that when two lines are parallel it means that they have the same slope. Therefore the slope of the line we are trying to find is also -4. We now know that:
Therefore the equation of the line is:
10% of 46.80 =4.68
46.80 + 4.68 = 51.48
Hope this helps :D
Answer:
Step-by-step explanation:
buenas tardes .....
solucion
Volumen de un cilindro: es igual al área de la tapa por la altura del mismo
A = πD² * h / 4
Lata grande y lata pequeña
Para la lata grande, el diámetro y la altura han aumentado un 20%.
Lata pequeña:
d = 4 cm
h = 3 cm
A 1 = π * (4) ² * 3/4
A1 = 37,70 cm²
Lata grande:
d = 4 * 1,2 = 4,8 cm
h = 3 * 1,2 = 3,6 cm
A2 = π (4,8) ²3,6 / 4
A2 = 65,14 cm²
Si 37,7 representa el 100%
65,14 representación x
x = 170%
El incremento del volumen es de un 70%
