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3 years ago

5

Find a degree 3 polynomials with real coefficient having zeros 2 and 4i and a leading coefficient of 1. Write P in expanded form

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1 answer:

Gelneren [198K]3 years ago

7 0

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Please help me answer this.

inna [77]

Answer:

D. 4,-1

Step-by-step explanation:

The mathmatical way to solev it is to find the linear equation and plug in the points, but i just looked at the graph to see which point was in the shaded region.

5 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

tresset_1 [31]

Because I've gone ahead with trying to parameterize $S$ directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over $S$ straight away, let's close off the hemisphere with the disk $D$ of radius 9 centered at the origin and coincident with the plane $y=0$ . Then by the divergence theorem, since the region $S\cup D$ is closed, we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV$

where $R$ is the interior of $S\cup D$ . $\vec F$ has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z$

so the flux over the closed region is

$\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0$

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0$

$\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0$

$\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}$

8 0

3 years ago

Javier's fuel tank holds 12 3/4 gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of

GenaCL600 [577]

Answer:

2.45 gallons of gasoline were in the tank before.

Step-by-step explanation:

Consider the provided information.

The tank can hold $12\frac{3}{4}$ gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of gasoline to fill it completely.

We need to find: How many gallons of gasoline were in the tank before Javier added some?

For this, we need to subtract added gallons of gasoline from the capacity of the tank.

$12\frac{3}{4}-10.3=\frac{51}{4}-10.3$

$=12.75-10.3$

$=2.45$

Hence, 2.45 gallons of gasoline were in the tank before.

6 0

3 years ago

How am i Invisible???????????????/

deff fn [24]

Answer:

being blind

Step-by-step explanation:

if you are blind you can not see your self so there for you are invisable

3 0

2 years ago

Read 2 more answers

Ed earns a $100 commission on each computer he sells plus a base salary of $50,000. His total income last year was $75,000. Whic

atroni [7]

50,000 + 100x = 75,000

He sold 250 Computers last year

5 0

2 years ago